I’m trying to construct an ANOVA table with my data , but the SSregr, SStotal, and SSerror are coming out negative. Are these correct, or am I doing something wrong? y = 60.7 +15.75X-constructed graph in excel+ SSErrorSS TOTAL = SSRegrS SERROR = 2 (Y₁-Y ) ²iHAY=114.25Biting force (Y) (121.6-114.257)³² = 54.02(111. 6-114.25)² = 7.02(96.7 - 114.25)² = 308.00(106.5-114.25) = 60.06( 129.0-114.25)² = 217.56(101.9-114.25)<= 152.52(134.4-114.25)² = 406.02(111.3-114.25)² = 8.70Residuel S SERROT & (Y₁-7)² = 1213.90Source of emerRegression✓ Error✓TotalANOVASSDFMSE (MS) FSSRegr1MSRegr +BsSx MsregS SError 1-2 MSError 0SS TOTALn-12SS TOTAL = EY² - (EY)² - 719436-( 913n8=-24760.13C.V.SeeMSError Table= SS EmerS STOTAL S Spear-24760113-1213.90 = -25974.03= SSError (x) headwidth | X²4.313.922.56Total:3.724.212.954.742.8427.1918.5715,366.5513.8317.728.7022.478.07111.271.18((P) Biting Force/Y ²121.6111.696.7106.512.9.0101.9134.4113.3913XY14786.5524.1012454.6 437.479350.9247.5511342.3396.1816641543.0910383.6 300.60518063.4635.06123877316.092794.363400.15

The data on head width(X) and biting force(Y) is given below sr no Head width(X)Biting…

(X) headwidth X² 4.31 3.92 2.56 Total: 3.72 4.21 2.95 4.74 2.84 27.19 18.57 15,36 6.55 13.83 17.72 8.70 22.47 8.07 111.27 (1) Biting Force / Y 2 121.6 111.6 96.7 106.5 129.0 101.9 134.4 113.3 913 14786.5 XY 524.10 12454.6 437.47 9350.9 247.55 11342.3 396.18 543,09 300.605 635.06 316.092 3400.15 16641 10383.6 18063.4 123877 794.36

(X) headwidth X² 4.31 3.92 2.56 Total: 3.72 4.21 2.95 4.74 2.84 27.19 18.57 15,36 6.55 13.83 17.72 8.70 22.47 8.07 111.27 (1) Biting Force / Y 2 121.6 111.6 96.7 106.5 129.0 101.9 134.4 113.3 913 14786.5 XY 524.10 12454.6 437.47 9350.9 247.55 11342.3 396.18 543,09 300.605 635.06 316.092 3400.15 16641 10383.6 18063.4 123877 794.36

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

If there is an overall significant F in a one way ANOVA, can we conclude that the group membership or treatment variable caused the observed differences in the group means? Why or Why not?
The leader of two postpartum women’s support groups is interested in the depression levels of the women in her groups. She administers the Center for Epidemiologic Studies Depression Scale (CES-D) screening test to the members of her groups. The CES-D is a 20-question self-test that measures depressive feelings and behaviors during the previous week. The mean depression level from the screening test for the 10 women in the first group is μ₁ = 16; the mean depression level for the 14 women in the second group is μ₂ = 10. Without calculating the weighted mean for the combined group, you know that the weighted mean is:
Why do we conduct a post hoc analysis in ANOVA? to make a comparison of individual adjuster R-square to make a comparison of the group means to make a comparison of individual unadjusted R-square none of the above
State the two-way ANOVA identity for degrees of freedom and interpret its meaning with regard to partitioning the total degrees of freedom in the data.
For what is two-way ANOVA used?
When and why would you conduct an ANOVA rather than a t-test?
When the One-Way ANOVA result is significant, that is, the Ho will be rejected, a follow-up test must be performed to determine which particular pairs of groups significantly differ. The follow-up test procedure is referred to asA. Pair-by-pair t-tests.B. Multiple t-testsC. Post-hoc analysisD. Tukey's HSD Test
When an egg is removed from the nest of a goose, the goose will roll it back into the nest with its beak. (Run a one-way ANOVA on the data. Provide a complete summary table.) Small Medium Large 10 10 15 12 14 16 11 13 17 13 14 14 15 15 17 11 16 17 12 14 14
for a two way factor anova comparing the possible interaction between religion and anxiety, what is the alternative
Suppose you are a product engineer for a tool manufacturing company, and want to investigate the strength of several new prototype redesigns of one of your drills. You have 13 new drill designs and would like to include a control group also of the original drill design. Your firm has decided to sample 37 drills for each new drill design and 37 drills in the control group with the original design. Using this information, if you were to conduct an ANOVA test based on a quantitative measure of the drill's performance, what is the degree of freedom associated with the variation within groups (SSE) in this analysis (denominator degree of freedom)?