NameDateThree different makes of cars were tested for fuel efficiency. For each make of car fifteen automobileswere randomly selected and subjected to standard driving procedures. Using the data from the followingresults compute the between treatments estimate of o² and the within treatments estimate of o?. At thea=.05 level of significance, can the null hypothesis, that all fuel economies are the same, be rejected?Construct the ANOVA table for this data. (Use the formulas to compute the needed values by hand.)1.FordChevroletChryslerMiles Per Gallon322934Standard Deviation4APR17étv 43.w/

The null and alternative hypotheses are; Null hypothesis: All the fuel economies are the same.…

Answered: Name Date Three different makes of cars…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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7. Consider the following ANOVA table for a multiple regression model: Source df SS MS F Regression 118.8475 59.42375 40.92168993 Residual 13.0692 1.452133333 Total 11 131.9167 a) Complete the remaining entries in the table. e) Test the significance of the overall regression model using a=0.05.
The data below pertain to the flourometric determination of the riboflavin content of dired collard leaves. Two factors were measured: 1) the size of the sample (.25 g vs 1.0 g) and 2) the effect of the inclusion of a clarification step in the determination process (with vs without). Do either of these factors have a significant effect on the apparent riboflavin concentration? Analyze these data used a nested ANOVA using the clarification step as the top level. Put your answers in standard format: hypotheses and conclusions relative to the hypotheses. Size Clarification Step 0.25g 1.00g Without 39.5 38.6 43.1 39.5 45.2 33 With 27.2 24.6 23.2 24.2 24.8 22.2
Consider the following measurements of blood hemoglobin concentrations (in g/dL) from three human populations at different geographic locations: population1 = [ 14.7 , 15.22, 15.28, 16.58, 15.10 ] population2 = [ 15.66, 15.91, 14.41, 14.73, 15.09] population3 = [ 17.12, 16.42, 16.43, 17.33] Perform ANOVA to check if any of these populations have different mean hemoglobin concentrations. (Assume that all the ANOVA requirements such as normality, equal variances and random samples are met.) After you perform ANOVA perform a Tukey-Kramer post-hoc test at a significance level of 0.05 to see which populations actually have different means. As usual, round all answers to two digits after the decimal point. (Make sure you round off to at least three digits any intermediate results in order to obtain the required precision of the final answers.) For any questions, which ask about differences in means or test statistics, which depend on differences in means provide absolute values. In…
The table below summarizes data from a survey of a sample of women. Using a 0.01 significance level, and assuming that the sample sizes of 900 men and 300 women are predetermined, test the claim that the proportions of agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does it appear that the gender of the interviewer affected the responses of women? what is the test static? what is the critical value? what is th P-value? Gender of Interviewer Man Woman Women who agree 572 243 Women who disagree 328 57 Chi-square Degrees of Freedom 0.995 0.99 0.975 0.95 0.90 0.10 0.05 0.025 0.01 0.005 1 - - 0.001 0.004 0.016 2.706 3.841 5.024 6.635 7.879 2 0.010 0.020 0.051 0.103 0.211 4.605 5.991 7.378 9.210 10.597 3 0.072 0.115 0.216 0.352 0.584 6.251 7.815 9.348 11.345…
Look at the ANOVA table. These are the results of an experiment that was done to test whether C (soil carbon) would differ after various methods of site prepartation before tree seedlings were planted. To measure carbon in the soil, the 0-5 cm and 6-10 cm topsoil depths were sampled and analyzed for C. Thus, there were 2 depths, 3 treatments sampled about 26 years after site prepartation occured. a. How do we test the significance of ANOVA? b. One of the assumptions of ANOVA is that the variance of Y is the same for all x values (Xi). What is meant by that statement?
Find the critical value for a test for correlation with α = 0.01 for a sample size of 18.
Suppose you conduct a 1-way ANOVA, in which you are comparing a continuous measure of immune response between 3 treatment groups (A, B, and C). The overall alpha level is set at 0.05. You ask for all pairwise comparisons, and you find that the unadjusted p-values for these comparisons are as follows: A vs. B: p=0.0333 A vs. C: p=0.1500 B vs. C: p=0.0100 Which of the following statements is true? Question 20 options: No correction for multiple hypothesis testing would be necessary in this situation. After a Bonferroni correction, the difference between groups B and C would remain statistically significant. After a Bonferroni correction, none of the p-values would remain statistically significant. After a Bonferroni correction, the difference between groups A and B and between groups B and C would remain statistically significant. After a Bonferroni correction, all of the p-values would remain…
I dont know wheere start with this ANOVA question Bonferroni correction, Thankyou. I have included table B2
A researcher is interested in the relationship between cigarette smoking and BMI (kg/m2) in adolescents. In order to test his hypothesis, the researcher decides to divide cigarette smoking into four groups based on the number of cigarettes smoked per day versus a control group of never smokers. The following incomplete ANOVA table summarizes a preliminary analysis for the difference in mean BMI for the groups. Sum of Squares df Mean Square Between Groups 54 Within Groups 38 Total 197 Fill in the ANOVA table above for all missing values. B) Calculate your F statistic for the one way analysis of variance.
Consider the following measurements of blood hemoglobin concentrations (in g/dL) from three human populations at different geographic locations: population1 = [ 14.7 , 15.22, 15.28, 16.58, 15.10 ] population2 = [ 15.66, 15.91, 14.41, 14.73, 15.09] population3 = [ 17.12, 16.42, 16.43, 17.33] Perform ANOVA to check if any of these populations have different mean hemoglobin concentrations. (Assume that all the ANOVA requirements such as normality, equal variances and random samples are met.) After you perform ANOVA perform a Tukey-Kramer post-hoc test at a significance level of 0.05 to see which populations actually have different means. As usual, round all answers to two digits after the decimal point. (Make sure you round off to at least three digits any intermediate results in order to obtain the required precision of the final answers.) For any questions, which ask about differences in means or test statistics, which depend on differences in means provide absolute values. In…
Consider the following ANOVA table for a multiple regression model relating housing prices (in thousands of dollars) to the number of bedrooms in the house and the size of the lot on which the house was built (in square feet). There were 9090 total observations. Estimated Price=20,160.07+2188.83(Bedrooms)+0.2139(Lot Size)Estimated Price=20,160.07+2188.83(Bedrooms)+0.2139(Lot Size) ANOVA dfdf SSSS MSMS F� Significance F� Regression 22 306,443.7975306,443.7975 153,221.8988153,221.8988 21.727421.7274 2.2211E-082.2211E-08 Residual 8787 613,525.5190613,525.5190 7052.01757052.0175 Total 8989 919,969.3165919,969.3165 What percent of variation in housing prices is explained by the number of bedrooms and lot size? Round your answer to two decimal places
A psychologist examines retention of a learned task in monkeys. At 90 days 5 monkeys are trained on a discrimination task. Then their performance is tested again at 4 months, 6 months, and 1 year. A partial ANOVA summary table follows. The data were analyzed using a repeated-measures ANOVA. Answer the following: Describe the null and alternative hypotheses. Then complete the source table. Source Between treatments SS df MS F 11 Within treatments Between subjects Error 40 Total 143

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