**Study Overview:**A cognitive psychologist is investigating whether the type of music played at gyms affects the number of days participants attend the gym over a month. Four different gyms, each with a unique musical format, are selected for this study. Eight gym members are randomly chosen from each gym, and their attendance is tracked for 30 days.**ANOVA Summary Table:**The table below outlines the Analysis of Variance (ANOVA) used to analyze the data. The significance level is set at $\alpha = 0.02$.| Source | SS | df | MS | F | P ||----------|-----|----|------|-------|----|| Between | | | 13.64| 2.788 | || Within | | | | | || TOTAL | | | | | |**Explanation of Table Columns:**- **Source:** Identifies the source of variance (Between and Within groups are typically analyzed).- **SS (Sum of Squares):** Represents the variability in the data.- **df (Degrees of Freedom):** Details the number of values that can vary for each source of variance.- **MS (Mean Square):** Calculated by dividing SS by df for each source, indicating the average variance.- **F (F-ratio):** A statistic used to determine if the means between groups are significantly different.- **P:** The p-value, used to decide whether to reject the null hypothesis at a specific significance level. The table is currently incomplete and requires additional data for SS, df, and potentially P. This information will reveal whether music type significantly affects gym attendance.

Answered: Image /qna-images/answer/923f0d2a-2e9e-4790-94f8-3ccab184c9f6.jpg

Answered: A cognitive psychologist studying…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Women are recommended to consume 1720 calories per day. You suspect that the average calorie intake is different for women at your college. The data for the 12 women who participated in the study is shown below: 1837, 1618, 1820, 1846, 1640, 1700, 1655, 1473, 1563, 1840, 1796, 1854 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = H1:H1: ? p μ Select an answer ≠ = < > The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean…
Women are recommended to consume 1700 calories per day. You suspect that the average calorie intake is different for women at your college. The data for the 12 women who participated in the study is shown below: 1784, 1677, 1583, 1984, 1910, 1737, 1522, 1574, 1853, 1546, 1707, 1866 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.)
The manager of a political party wants to find out the association between the campaign spending (Large, medium and small) and the vote obtained (Majority, Average and minority). Use Chi-squared hypothesis test for association to test that there is an association between the variable in campaign spending and the variable in vote obtained with five percent level of significance. The manager uses MS excel to calculate the Chi-squared stat value and the result is 8.874. Critical value: At 1% = 13.277 :At 5% = 9.488 :At 10% = 7.779 1. State the decision rule 2. Conclusion and decision 3. State the alternative hypothesis and the null hypothesis
Consider the following measurements of blood hemoglobin concentrations (in g/dL) from three human populations at different geographic locations: population1 = [ 14.7 , 15.22, 15.28, 16.58, 15.10 ] population2 = [ 15.66, 15.91, 14.41, 14.73, 15.09] population3 = [ 17.12, 16.42, 16.43, 17.33] Perform ANOVA to check if any of these populations have different mean hemoglobin concentrations. (Assume that all the ANOVA requirements such as normality, equal variances and random samples are met.) After you perform ANOVA perform a Tukey-Kramer post-hoc test at a significance level of 0.05 to see which populations actually have different means. As usual, round all answers to two digits after the decimal point. (Make sure you round off to at least three digits any intermediate results in order to obtain the required precision of the final answers.) For any questions, which ask about differences in means or test statistics, which depend on differences in means provide absolute values. In…
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Is there a significant relationship between income and the level of work adjustment of the individual with hearing impairment? Use a=0.05 level of significance and n = 32. What is the alpha level of significance?
A study from 2014 found that adults in the US spend an average of 11 hours per day watching, reading, listening to or simply interacting with media. Researchers at UCLA suspect students spend less time engaging media. They grouped UCLA students by class section, randomly selected 20 class sections, and administered a survey to each student in those randomly selected class sections. The following data represents the mean time (in hours) per day spent engaging media for each of the randomly selected classes: 9.5 11.5 6.0 7.5 8 9.5 10.5 11 12 8.2 5 9.5 8.2 9.3 10.8 11 13 8.6 9.5 10.5 What would be the calculator steps to find standard deviaton, rounded to 3 decimal places?
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