A clinical study was conducted on a medicineand the data obtained as follows: calculateSensitivityDiseased•True Positive: 1000•True negative: 50Non diseased•True positive: 100•True negative: 800

Answered: A clinical study was conducted on a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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PLEASE ANSWER ASAP: A case-control study was conducted to evaluate the relationship between physical activity and coronary heart disease (CHD) in men. A total of 406 men newly diagnosed with CHD were included together with 406 men of similar ages who did not have CHD. The risk of CHD (measured by the OR) was higher among men who were inactive or only moderately active (collectively called ‘inactive’) than among those who were physically active: (See attached image) Odds ratio for inactive men compared to active men= (299 x 136)/(270 x 107)=1.41Suppose there is no misclassification in these data.What would the observed OR have been... 1. If 20% of all the inactive men had been misclassified as active? 2. If 10 % of inactive cases had been misclassified as active?
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
An investigator is using a chi-square test to compare the proportion of patients with a successful recovery after receiving one of 4 treatments. There were 25 subjects in each group. What is the critical value for testing no association or treatment and response?
You recently had a cholesterol panel completed and see that the results for your High Density Lipoprotien (HDL) level comes back with z = -1.7 among people of your stature. Your doctor is going to review the results with you but based on what you know about z-scores you can infer: a.The average person of your stature is 1.7 deviations below you. b.Your HDL level is slightly below average. c.The score is negative so this will be good news. d.Your HDL level is extremely low for a person of your stature.
This research was conducted with Korean adolescents in the Los Angeles area. Would you be willing to generalize the results of this study to Korean adolescents who live in other regions of the country? Why or why not.
Please answer these questions thanks
A certain prescription medicine is supposed to contain an average of 250 parts per million (ppm) of a certain chemical. If the concentration is higher than this, the drug may cause harmful side effects; if it is lower, the drug may be ineffective. The manufacturer runs a check to see if the mean concentration in a large shipment conforms to the target level of 250 ppm or not. A simple random sample of 100 portions is tested, and the sample mean concentration is found to be 247 ppm. The sample concentration standard deviation is s = 12 ppm. What are the appropriate null and alternative hypotheses? Group of answer choices H 0: x̄ = 250 vs. H a: x̄ < 250 H 0: x̄ = 250 vs. H a: x̄ ≠ 250 H 0: x̄ = 250 vs. H a: x̄ > 250 H 0: μ = 250 vs. H a:μ < 250 H 0: μ = 250 vs. H a: μ ≠ 250 H 0: μ = 250 vs. H a: μ > 250
he data on the number of chocolate chips per bag for 42 bags of Chips Ahoy! cookies were obtained by the students in an introductory statistics class at the United States Air Force Academy in response to the Chips Ahoy! 1,000 Chips Challenge sponsored by Nabisco, the makers of Chips Ahoy! Use the data collected by the students to answer the following questions and to conduct the analyses required in each part. They found ¯xx¯ = 1261.6 and s = 117.6 a. Determine a 95% confidence interval for the mean number of chips per bag for all bags of Chips Ahoy! cookies. ≤μ≤≤μ≤ b. Interpret your result in words. c. Can you conclude that the average bag of Chips Ahoy! Cookies contain at least 1000 chocolate chips? yes no
Show the impact of sample size on power?
Ride services are on the rise, such as Uber and Lyft. You wondered if the recent news reports of crime occurring with these ride services impacted the usage of them, especially with women. You decide to conduct a survey about ride service usage among male and female college students. The results showed that 19 males use ride services and 11 do not. While 12 females use ride services and 18 do not. Calculate the chi-square statistic:
In intaglio printing, a design or figure is carved beneath the surface of hard metal or stone. Suppose that an experiment is designed to compare differences in mean surface hardness of steel plates used in intaglio printing (measured in indentation numbers), based on two different surface conditions-untreated and treated by lightly polishing with emery paper. In the experiment, 40 steel plates are randomly assigned-20 that are untreated, and 20 that are treated. The results of the experiment are in the “Intaglio” data in Chapter 10_HW_Data.xls. Assuming that the population variances from both conditions are equal, is there evidence of a difference in the mean surface hardness between untreated and treated steel plates? (use α = 0.05) Determine the p-value in (a) and interpret its meaning. In addition to equal variances, what other assumption is necessary in (a)? Repeat Problem (a), assuming that the population variances from untreated and treated steel plates are not…
Alpha equals 0.01 level of significance for the given sample data.

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A clinical study was conducted on a medicine and the data obtained as follows: calculate Sensitivity Diseased •True Positive: 1000 True negative: 50 Non diseased •True positive: 100 •True negative: 800