A clinical study was conducted on a medicine and the data obtained as follows: calculate Sensitivity Diseased •True Positive: 1000 True negative: 50 Non diseased •True positive: 100 •True negative: 800
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- Water specimens are taken from water used for cooling as it is being discharged from a power plant into a river. It has been determined that as long as the mean temperature of the discharge is at most 150F, there will be no negative effects on the river's ecosystem. To investigage whether the plant is in compliance with regulations that prohibit a mean discharge water temperature above 150F, researchers will take 50 specimens at randomly selected times and record the temperature of each specimen. The resulting data will be used to test the hypotheses:H0:μ≤150FH0:μ≤150F Ha:μ>150FHa:μ>150F.(a) In the context of this problem, describe Type I and Type II errors.Type I Error:Select an answer A Type I error is not obtaining convincing evidence that the mean water temperature is greater than 150F when in fact it is greater than 150F. A Type I error is obtaining convincing evidence that the mean water temperature is greater than 150F when in fact it is at most 150F. Type II…A researcher gathered a sample of participants who volunteered for a studying of phobias. She measured anxiety level of participants as they viewed photos of spiders and again when they viewed puppies. Which statistical test is appropriate for this study and why?Á study was conducted that examined the relationship between alcohol consumption and risk of heart attack. In all, 417 men, age 40 or older, were tracked over ten years and the number of that experienced a heart attack was recorded. The participants were grouped by those who totally abstained from alcohol and those that drank moderately. For the results given in the table below, use the chi-squared test to find the p value for NHST at the .05 level. (In SPSS use the Yates continuity correction value.) Heart attack Alcohol Crosstabulation Count Alcohol Abstainer Moderate Total Heart attack No 197 192 389 Yes 9. 19 28 Total 206 211 417 Op= .090 Op= 121 !! Op=.067 Op = .048
- A social psychologist recently developed a childhood-memories test that is intended to measure how people recall pleasant and unpleasant experiences from childhood. Scores on the test range from 1 (very unpleasant) to 100 (very pleasant). The psychologist standardized the test with a large group of college students (ages 18-25), and the mean score was p=60. The test was then given to a sample of n=25 individuals who were all between the ages of 40 and 45. The average score for this sample was 64.3 with SS (sum of squares)=600. Note: S?=SS÷df (variance is equal to sum of squares divided by the degrees of freedom). What is your standard deviation? Answer:A hypertensions trial is mounted and 12 participants are randomly assigned to receive either a new medication or a placebo. Each participant takes assigned medication and their systolic blood pressure (SBP) is recorded after 6 months on the assigned medication the data are shown in table 7-9 is there a difference in the mean SBP between treatment? Run the appropriate test at a =0.05The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. Is there any difference in mean life of these two brands of tires? Car Brand Brand 36,925 34.318 42,280 1 45.300 36,240 3 4 35.500 32,100 31,950 38,015 37.210 48,360 5 47,800 38,200 37,810 33.500 33,215 6. 7 8. 1. Is this samples independent or paired samples? Explain. 2. Write Ho and H1 3. Calculate Test statistics(T). 4. What is the critical value (T from tables)? 5. What is your conclusions if a = 0.05? 6. Estimate with 90% confidence the different in the means. Which brand would you prefer based on this calculation?
- A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 75 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. N Mean StDev SE Mean Men Women 95% Cl for mu Men - mu Women - 9.81, - 0.79) T-Test mu Men = mu Women (vs H2 Oc. Họ: H1 = H2; Hai H1A random sample of 50 CSCC students are surveyed to determine what percent of our students are first-generation college students. The results showed that 16 of the students identify as first-generation college students. show your work What is the sample proportion of first-generation college students at CSCC? Is this an example of a parameter or a statistic? Explain.An environmental group conducted a study to determine whether crows in a certain region were ingesting food containing unhealthy levels of lead. A biologist classified lead levels greater than 6.0 parts per million (ppm) as unhealthy and that the distribution of the population of crows was Normally distributed. The lead levels of a random sample of 23 crows in the region were measured and recorded. The mean lead level of the 23 crows in the sample was 4.90 ppm and the standard deviation was 1.12 ppm. B.A previous study of crows showed that the population standard deviation was at 2.6 ppm. What minimum sample size would be required to construct a 90 percent confidence interval to have a margin of error within 0.03?undergraduate students taking a concepts and methods course at the university conducted a survey about GPA and major. There were 197 total students and 3 groups of majors that were randomly sampled. The mean square within groups was 0.081 and the mean square between groups was 0.015. What F-statistic output is correct for this problem?A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 59 men and 73 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. SE Mean 1.5 1.7 SIDev 11.2 Mean 112.7 Men Women 99% CI for mu Men - mu Women -11.89, 0.09) T-Test mu Men mu Women (vs<) T= -2.61 P=0.0051 DF 129 59 73 118.6 14.8 Two sample T for Men vs Women State the researcher's condlusion. Which of the following is correct? O A Reject Ha, there is sufficient evidence to condlude that the mean step pulse of men was less than the mean step pulse of women the mean step pulse of women O B. Reject Ha, there is not sufficient evidence to condlude that the mean step pulse of men was less OC. Fail to reject Ho, there is sufficient evidence to conclude that the mean step pulse of men was less than the mean steg pulse of women O D.…The SSRUR = 161.9, SSRR = 260.6, number of restrictions = 2, n = 89, and there are 8 right hand side variables. Calculate the F statistic.
