In a random consumer survey, randomly selected drivers of Porsche, Mercedes, and BMW were asked to rank their satisfaction with their respective cars on a scale from one to ten where higher values indicate greater satisfaction. Porsche Mercedes BMW 10 8 0 8 6 4 6 10 2 Please conduct an F-Test on H0: There is no difference among Porsche, Mercedes, and BMW drivers HA: There is at least one difference To answer the following questions, refer to the below ANOVA Table: Sum of Squares Degrees of freedom: Mean Sum of Squares Between Cell A: Cell D: Cell F: Within Cell B: Cell E: Cell G: Total Cell C: F-Stat: What's the value of cell A? A 24 B 48 C 72 D 96 What's the value of cell B? A 24 B 48 C 72 D 96 What's the value of cell C? A 24 B 48 C 72 D 96 What's the value of cell D? A 1 B 2 C 6 D 9 What's the value of cell E? A 1 B 2 C 6 D 9 What's the value of cell F? A 4 B 9 C 36 D 40 What's the value of cell G? A 4 B 9 C 36 D 40 What's the value of the F-Stat? A 4 B 9 C 36 D 40 From an F-table or using Excel, you can infer that the p-value is A Less than 0.01 B Between 0.01 and 0.025 C Between 0.025 and 0.05 D More than 0.05 Assume that you reject the null hypothesis of no-difference at �=0.05. This means that you hypothesize that there is no difference in the population regarding driver satisfaction. Then, if the probability of getting a sample with your observed differences has a probability of less than 5% to be drawn from a population with no differences, you reject the null hypothesis. As a statistics expert, you A reject the null B fail to reject the null C wouldn't know what to do D would flip a coin to decide
In a random consumer survey, randomly selected drivers of Porsche, Mercedes, and BMW were asked to rank their satisfaction with their respective cars on a scale from one to ten where higher values indicate greater satisfaction.
Porsche |
Mercedes |
BMW |
10 |
8 |
0 |
8 |
6 |
4 |
6 |
10 |
2 |
Please conduct an F-Test on
H0: There is no difference among Porsche, Mercedes, and BMW drivers
HA: There is at least one difference
To answer the following questions, refer to the below ANOVA Table:
|
Sum of Squares |
Degrees of freedom: |
Mean Sum of Squares |
|
Between |
Cell A: |
Cell D: |
Cell F: |
|
Within |
Cell B: |
Cell E: |
Cell G: |
|
Total |
Cell C: |
|
|
F-Stat: |
What's the value of cell A?
A
|
24 |
B
|
48 |
C
|
72 |
D
|
96 |
What's the value of cell B?
A
|
24 |
B
|
48 |
C
|
72 |
D
|
96 |
What's the value of cell C?
A
|
24 |
B
|
48 |
C
|
72 |
D
|
96 |
What's the value of cell D?
A
|
1 |
B
|
2 |
C
|
6 |
D
|
9 |
What's the value of cell E?
A
|
1 |
B
|
2 |
C
|
6 |
D
|
9 |
What's the value of cell F?
A
|
4 |
B
|
9 |
C
|
36 |
D
|
40 |
What's the value of cell G?
A
|
4 |
B
|
9 |
C
|
36 |
D
|
40 |
What's the value of the F-Stat?
A
|
4 |
B
|
9 |
C
|
36 |
D
|
40 |
From an F-table or using Excel, you can infer that the p-value is
A
|
Less than 0.01 |
B
|
Between 0.01 and 0.025 |
C
|
Between 0.025 and 0.05 |
D
|
More than 0.05 |
Assume that you reject the null hypothesis of no-difference at �=0.05. This means that you hypothesize that there is no difference in the population regarding driver satisfaction. Then, if the probability of getting a sample with your observed differences has a probability of less than 5% to be drawn from a population with no differences, you reject the null hypothesis. As a statistics expert, you
A
|
reject the null |
B
|
fail to reject the null |
C
|
wouldn't know what to do |
D
|
would flip a coin to decide |
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