Consider the following data. Construct an ANOVA table without using excel Factor B= 1Factor B-2Factor A=1(6.07,8.67,0.48)(11.45,9.87, 11.43)Factor B-3 (10.98, 12.07, 11.45)Factor A=2(0.72,-0.36,-3.61)(3.59, 3.75, 6.98)(3.39, 4.59, 2.42)Factor A=3(9.13, 10.69, 17.16)(17.82, 17.83, 16.34)(16.78, 12.71, 12.86)Construct an ANOVA table to assess the null-hypotheses i) there is no interac-tion effect, ii) there is no Factor A effect, and iii) there is no Factor B effect.Perform these tests at significance level a = 0.05.Factor A=4(16.54,8.30, 17.07)(13.59, 17.43, 19.26)(14.38, 10.11, 18.88)

We have to test the following null hypotheses: H01: There is no intercation effect. H02: There is no…

Answered: (10.98, 12.07, 11.45) (3.39, 4.59,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(10.98, 12.07, 11.45) (3.39, 4.59, 2.42) (16.78, 12.71, 12.86) NOVA table to assess the null-hypotheses i) there is no interac- here is no Factor A effect, and iii) there is no Factor B effect. sts at significance level a= 0.05.