2. From these k-mers construct a de Bruijn graph anddetermine the sequence of the contig.AGCG ATCT ATGA ATGG ATTC CCCT CCTG CTCT CTGACTGC CTTT GAAG GATT GCGT GCTC GTTC TATG TCATTCTA TCTT TGAA TGAT TGGA TGTT TTCA TTCC TTTC

introduction In graph theory, an -dimensional De Bruijn graph of symbols is a directed graph…

Answered: rmine the sequence of the contig. G…

rmine the sequence of the contig. G ATCT ATGA ATGG ATTC CCCT CCTG CTCT CT C CTTT GAAG GATT GCGT GCTC GTTC TATG TO TOTT TCAA TCAT TCCA TCTT TTCA TTC C TT

Anatomy & Physiology

1st Edition

ISBN:9781938168130

Author:Kelly A. Young, James A. Wise, Peter DeSaix, Dean H. Kruse, Brandon Poe, Eddie Johnson, Jody E. Johnson, Oksana Korol, J. Gordon Betts, Mark Womble

Publisher:Kelly A. Young, James A. Wise, Peter DeSaix, Dean H. Kruse, Brandon Poe, Eddie Johnson, Jody E. Johnson, Oksana Korol, J. Gordon Betts, Mark Womble

Chapter3: The Cellular Level Of Organization

Section: Chapter Questions

Problem 17RQ: Which of the following sequences on a DNA molecule would be complementary to GCTTATAT? TAGGCGCG...

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PLEASE MAKE THE DR BRUJIN GRAPH From these k-mers construct a de Bruijn graph and determine the sequence of the contig. AGCG ATCT ATGA ATGG ATTC CCCT CCTG CTCT CTGA CTGC CTTT GAAG GATT GCGT GCTC GTTC TATG TCAT TCTA TCTT TGAA TGAT TGGA TGTT TTCA TTCC TTTC
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Second letter A G UCU UCC UAU. Tyr UAC. UUU1 Phe UUC. UUA UUG. UGC Ser }Leu UAA Stop UGA Stop UAG Stop |UGG Trp UCA UCG CAU His CUU CỤC CCU ССС ССА CGU CGC Arg Leu CÁCS Pro CỦA CUG CGA CAAGIN CGG, Gln CAG, CCG J AAU Asn ACU АСC АСА AUU AGU Ser AUC }le A AUA AAC. Thr А AGC AGA AUG Met | ACG ] AAG Lys AG. GUU GUC GCU GAU1 AAsp GACS Ala GAA GGU GGC GCC Val Gly GGA G GUA GCA GUG GCGJ GAG Glu GGG Which peptide is the least likely to be made on the ribosome and why? а. Third letter DUAG 5UAG DUAG DUAG First letter
U UUU UAU 11yr Phe UUC UUA Leu UUG Jle UCU UCC UCA UCG UGU UGC Cys UGA Stop UAG Skop UGG Trp UAC Ser UAA Stop CUU CUC CỦA CUG CAU JHis CAC CGU CGC CGA CGG CCC Leu Pro Arg ССА Delete CCA CG CAA CAG JGIN Gln AUU AUC le AUA AUG Met AGU 1 Ser AGC AGA AGGJArg 1. ACU ACC The ACA ACG AAU M AAC AAA AAG Jlys JAun ATG AAC TAC CTA GGG ACA GAU JAsp GAC GAA GAG JGlu GUU GUC Val G GUA GCU GCC GCA Ala GCG GGU GGC Gly ATG ACC TAG GGA CA GGA GGG GUG G. Compare translation before and after the deletion. What effect might it have on gene function? Asp Daspartic acid lleI isolcucine Thr T threonine Leu L leucine Ser S serine Туr Y tyrosine Glu E glutamic acid Phe F phenylalanine Pro P proline His H histidine Lys K Arg R Gly G glycine lysine Ala A alanine arginine Cys C cysteine Trp W tryptophan Val V valine Gln Q glutamine Met M methionine Asn N asparagine Second Position UGU 1Cy UCU UCC Ser UCA UG UUU Phe UAU UAC Ty UAA Slop UGA Stop UAG Slop UGG Trp UGC UUC U UUA Leu ] low UUG CUU CÚC A Leu CCU CCC Pro…
5’- TTGACATGCG ATGTCGTAGG GATATATAAT CCACACAGTC GACAATTGAC ATCCCGGTCA CCTATAATCG TGAACACATA TAAGGAGTCT GACTATGGTA AGTAAATATG GTCATTAGTT ATGTGAACAG CCATTGGAGT CCACACTGAC TGAGATTAAG AGATGCCGAT AAAGTGGATA GCATTTTAAC TTGACAATGG ACGATCGATC GTAATTACCA ATGTGAATCG TAGTTGCGCA TTTCGGACGT -3’ a) Counting from the first nucleotide (A) of the Shine-Dalgarno consensus sequence, show the sequence of the first 20 nucleotides in the mRNA encoded by this piece of DNA (specify 5’ & 3’ ends). b) What is the sequence of protein X (specify the amino and carboxyl termini)? c)A mutation occurs in the original DNA strand for protein X such that the adenosine nucleotide at position +35 is deleted. What is the effect of this mutation? d) A mutation occurs such in the original DNA for protein X strand such that the adenosine nucleotide at position +48 is changed to a thymine. What is the effect of this mutation?
7. Draw the protein: SRDR Second letter A UCU UCC UCA UAU) UUU UUC UUA Leu UCG UUG UGU UGCys Phe UACTyr UAA Stop UGA Stop A Ser UAG Stop UGG Trp G CAUHS CUU CUC CGU CGC CCU CAC, Pro CAA Arg CGA FLeu CCA CCG CUA CUG CAGGin CGG AGU AAU AS AUU AUC le AUA AUG Met ACG ACU ACC ACA Asn Ser AAC The AGC AGA AAA AAGLys AGG Arg GUU GUC G. Val GUA GUG GCU GCC Ala GCA GGU Asp GGC GAU GACJ GAA GAG Gly GGA GCG GGG First letter Third letter
C A UUU U UUC Phe UCU UCC UCA UAU UAC UAA UAG UGU Cys U UGC Stop UGA Stop Stop UGG Trp G Tyr Ser UUA UUG Leu UCG CUU C CUC CUA CCU Leu ccc CCA CCG CAU CAC CAA His CGU CGC CGA CGG Pro Arg 1st Gin CUG CAG 3rd letter AUU A AUC AUA AUG ACU AAU AAC Ser u letter C Asn AGU AGC AGA AGG lle ACC Thr ACA AAA AAG Lys Arg Met ACG GUU G GUC GUA GUG GCU GCC GCA GCG GAU GAC GAA GAG Asp GGU GGC GGA GGG Val Ala Gly Glu Not all of the following ingredients are necessary for an in vitro translation reaction. Which one would you leave out? A ssDNA template O Cell sap containing ribosomes poly(U) O 14C-Phe
AGTGCAGCTC CAGCCGACCC CCGGGACGTA GACAAGGGCA GGCGCGCGGT 50 GAAGACTGCG GCCGGCCGCG TAGCCGCGCT GTGGTCCCGC TGGCCTTCTC 100 TTGGGCCGCG CACCCTCCGG ACCTGCGTCG GGATCCTCCC GGAGTCTCCC 150 GCTCTCTCCT CCCGGCTTGC GAACATGCGG CCCCTTAAGC CCGGCGCCCC 200 TTTGCCCGCA CTCTTCCTGC TGGCGCTGGC TTTGTCCCCG CACGGAGCCC 250 ACGGGAGGCC CCGGGGGCGC AGGGGAGCGC GCGTCACGGA TAAGGAGCCC 300 AAGCCGTTGC TTTTCCTCCC CGCGGCCGGG GCCGGCCGGA CTCCCAGCGG 350 CTCCCGGAGC GCAGAAATAT TCCCAAGAGA CTCTAACTTA AAAGACAAAT 400 TCATAAAGCA TTTCACAGGG CCGGTCACAT TTTCACCAGA ATGCAGCAAA 450 CATTTCCACC GACTCTATTA CAATACCAGG GAGTGCTCAA CGCCAGCTTA 500 TTACAAAAGA TGTGCTAGAT TGTTAACAAG ATTAGCAGTG AGTCCACTGT 550 GCTCCCAGAC CTAGCAAAAC TACCCTACAT TTCCTAAGAA TGTACATCTA 600 ATTTGAAGAA AAAGTGCCTC AAATCATGCA AAATGTAAAA AAAGATGAAA 650 TTTATATTTT TATGGATATT AAGATGAGTA AAATAAGAGA CTTCCCAGAA 700 ATAACTGGTT AGCTGTTTCC TGTCATAGAA TGGAGTCTTT CTTGCTTTAT 750 CTTTTTGTGT ATACAGTAAT TTATAATTTT GTAAAACAGA GTTTGAATCG 800 CATATTGAAA ATTAGATATT AAAAATTGTG…
Page 1: Second Letter C 1 2 UUU U UUC UUA Phe UCU UCC UCA UCG UAU UAC UAA UAG UGU Cys U UGC Stop UGA Stop UGG Tyr -- Ser Leu Stop A Trp G UUG CUU C CUC CCU Leu cc CAU His CGU Pro CAC CGC Arg CUA CUG CCA CCG 1st СА Gln CGA CAG CG 3rd letter AUU A AUC AUA AUG ACU ACC ACA AGU Ser AGC u letter AAU AAC AAA AAG Asn He Thr AGA AGG A Arg G Lys Met ACG GUU G GUC GUA GUG GCU GCC GAU Asp GGU GGC U Val GAC GAA GAG Ala Gly GCA GGA GGG Glu GCG 1. Convert the sequence from DNA to Amino Acids. 3-TCACCACTCTGGTCTGGTCATATCTGCCTGATATGAGTACAT - 5' a. direct transcript? b. transcript for translation? c. direction of a? (3' to 5' or 5' to 3') d. direction of a (3' to 5' or 5' to 3') e. translated peptides?
2. Here is the detailed view of the MCS of the PUC19 plasmid: Sma I KpnI SbfI PstI SacI XbaI ECORI BamHI Sall SphI HindIII agt GAATTCGAGCTCGGTACCCGGGGA TCCTCTAGAGTCGACCTGCAGGCATGCAAGCTTGGcgtaatcatggtcat 400 410 420 430 440 450 460 ...S N S SP VR PDEL TS R CAH LS P T IM T M lacZa translational start Figure 25: MCS of PUC19 A. If the MCS were cut with Kpn I and BamH I, draw the small fragment of DNA that would be cut out. Show both strands. For reference, here are the recognition sequences: 5' G|GAT СС 3' 3' С СТАG|G 5' recognition sequence for BamH I 5' G GTAC|C 3' 3' cl CATG G 5' recognition sequence for Kpn I Figure 26: recognition sequences for BamH I and Kpn I
Second letter UUU UUC UUA UUG. UCU UCC UCA UCG UAU Tyr UAC. Ser UAA Skp UGIA Stop UGU UGC. Phe Cys Leu UAG Sop UGG Trp CGU CGC Arg CGA CCU CAU CUU CUC CUA CUG His CAC CAA CAG Gin CCC Pro CCA Leu CCG CGG ACU AAUA AGU ]Ser AUU Asn AAC AGC AGA LArg AGG. AUC Be ACC ACA Thr AAA AUA AUG Met ACG MGys GUU GUC Val GUA GCU GCC GCA GCG Ala GAA Glu GAG GAU GAC Asp GGU GGC Gly GGA GGG GUG You come across four polynucleotide strands. The first is an original RNA strand that codes for a protein; the others are similar to the original RNA strand, except that each displays a point mutation. The point mutations are shown in red. 5' - AUG-UGC-AUU-CCU-GCA-UAA - 3' 5' - AUG-UGA-AUU-CCU-GCA-UAA - 3' 5' - AUG-UGC-AUU-CCC-GCA-UAA - 3' 5' - AUG-UGC-GUU-CCU-GCA-UAA - 3' Original RNA: Mutant RNA 1: Mutant RNA 2: Mutant RNA 3: 1. Based on how they will affect the protein product, identify the type of point mutation (missense, nonsense, silent, or frameshift) present in the Mutants 1, 2, and 3. 2. State which of…