Response (arbitrary units) Hexane r.t. = 1.25 min Methane r.t. = 0.50 min T Solute 1 r.t. = 1.78 min Heptane Octane r.t. = 2.47 min r.t. = 5.66 min Solute 2 r.t. 4.83 min 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 Time (min)
Response (arbitrary units) Hexane r.t. = 1.25 min Methane r.t. = 0.50 min T Solute 1 r.t. = 1.78 min Heptane Octane r.t. = 2.47 min r.t. = 5.66 min Solute 2 r.t. 4.83 min 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 Time (min)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
calculate the kovats retention indices for solutes 1 and 2 from the data shown and assume tm=0.50 min (methane)
![Response (arbitrary units)
Hexane
r.t. = 1.25 min
Methane
r.t. = 0.50 min
T
Solute 1
r.t. = 1.78 min
Heptane
Octane
r.t. = 2.47 min
r.t. = 5.66 min
Solute 2
r.t. 4.83 min
0 0.5
1
1.5
2
2.5
3
3.5
4 4.5
5
5.5
6
Time (min)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc0c930a-da4d-45e4-a49d-df883ca8386f%2F51e8cfdf-6f64-4c8e-bd62-626600275e0e%2F0lvtgb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Response (arbitrary units)
Hexane
r.t. = 1.25 min
Methane
r.t. = 0.50 min
T
Solute 1
r.t. = 1.78 min
Heptane
Octane
r.t. = 2.47 min
r.t. = 5.66 min
Solute 2
r.t. 4.83 min
0 0.5
1
1.5
2
2.5
3
3.5
4 4.5
5
5.5
6
Time (min)
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