Question 6. What are the first three amino acids in theprotein that is produced from this gene? Write the amino acidsusing the three-letter code separated by a hyphen.-35 sequence Pribnow box3'5' GATTCCGTATTACAGCATAGGCTATATT CACGTGGATGGTCAGTA...3' CTAAGGCATA ATGTCGTATCCGATATAAGTGCACCTA CCGATCAT... 5'Start site

Transcription:Transcription is the process by which the DNA sequence is converted into mRNA. In DNA,…

Answered: Question 6. What are the first three…

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter16: Gene Expression

Section: Chapter Questions

Problem 38CTQ: A scientist discovers a virus encoding a Protein X that degrades a subunit of the elF4F complex....

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Similar questions

A scientist discovers a virus encoding a Protein X that degrades a subunit of the elF4F complex. Knowing that this virus transcribes its own mRNAs in the cytoplasm of human cells, why would Protein X be an effective virulence factor?
An adult with a history of tanning has his genome sequenced. The beginning of a protein-coding region of his DNA reads ATGGGGATATGGCAT. If the protein-coding region of a healthy adult reads ATGGGGATATGAGCAT, identify the site and type of mutation.
Below is a sequence of 540 bases from a genome. What information would you use to find the beginnings and ends of open reading frames? How many open reading frames can you find in this sequence? Which open reading frame is likely to represent a protein- coding sequence, and why? Which are probably not functioning protein-coding sequences, and why? Note: for simplicitys sake, analyze only this one strand of the DNA double helix, reading from left to right, so you will only be analyzing three of the six reading frames shown in Figure 19.4.
A normal mRNA that reads 5’ - UGCCAUGGUAAUAACACAUGAGGCCUGAAC- 3’ has an insertion mutation that changes the sequence to 5' -UGCCAUGGUUAAUAACACAUGAGGCCUGAAC- 3’. Translate the original mRNA and the mutated mRNA, and explain how insertion mutations can have dramatic effects on proteins. (Hint: Be sure to find the initiation site.)
Helicase Unwinding of the E. coli Chromosome Hexameric helicases, such as DnaB, the MCM proteins, and papilloma virus El helicase (illustrated in Figures 16.22 to 16.25), unwind DNA by passing one strand of the DNA duplex through the central pore, using a mechanism based on ATP-dependent binding interactions with the bases of that strand. The genome of E. coli K12 consists of 4,686,137 nucleotides. Assuming that DnaB functions like papilloma virus El helicase, from the information given in Chapter 16 on ATP-coupled DNA unwinding, calculate how many molecules of ATP would be needed to completely unwind the E. coli K 12 chromosome.
Contrast transcription and translation. Name at least three differences between the two processes.
New drugs are being developed that decrease DNA methylation and prevent the removal of acetyl groups from histone proteins. Explain how these drugs could affect gene expression to help kill tumor cells.
Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also, write out the amino acid sequence of the protein encoded by this message. tRNA: UAC UCU CGA GGC mRNA: protein: How many hydrogen bonds would be present in the DNA segment?
Alternative Splicing Possibilities Suppose exon 17 were deleted from the fast skeletal muscle troponin T gene (Figure 29.46). How many different mRNAs could now be generated by alternative splicing? Suppose that exon 7 in a wild-type troponin T gene were duplicated. How many different mRNAs might be generated from a transcript of this new gene by alternative splicing?
The RNA components of ribosomes are synthesized in the.____ cytoplasm nucleus nucleolus endoplasmic reticulum
Prokaryotic cells lack a nucleus. Therefore, the genes in prokaryotic cells are: all expressed, all of the time transcribed and translated almost simultaneously transcriptionally controlled because translation begins before transcription ends b and c are both true
About 95% of the average human transcription unit consists of: a. short repeat sequences. b. protein-coding sequences. c. regulatory sequences. d. introns. e. origins of replication.

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