Q3/ For the Aluminum cantilever, shown in Fig.2 below, the factor of safety against fatigue is2.4, the sensitivity factor 0.7, the surface finish factor is 0.91, the size factor is 0.6, Sut 320 MPaand yield strength is 61 Mpa. Calculate, using a proper design theory, the diameter at the fillet.Neglect the transverse shear stress.Fig.20.2d-50 kN(15 Marks)100mm150kN200mm

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Answered: Q3/ For the Aluminum cantilever, shown…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Assume suitable value for any missing data. Two cylindrical parts are to be assembled to make an interference fit. The nominal diameter of the assembly is 100 mm. Before assembly, the inner member (copper) has an outer radius that is 0.2 mm larger than the inner radius of the outer member (aluminum). If there is no other force acting on the assembly, determine the maximum and minimum principal stress in both the members. Assume Poisson's ratio of 0.3 for both the materials. Also take rj = 30 mm for copper cylinder and ro = 80 mm for aluminum cylinder.
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! Required information A rectangular bar is cut from an AISI 1020 cold-drawn steel flat. The bar is 2.500 in wide by 4/8 in thick and has a 0.500-in-dia. hole drilled through the center as depicted in Table A-15-1. The bar is concentrically loaded in push-pull fatigue by axial forces Fa, uniformly distributed across the width. Using a design factor of na = 2, estimate the largest force Fã that can be applied ignoring column action. Determine the endurance limit for this material as well as the value after correction for surface finish, sizing, and loading. The endurance limit for the material is kpsi. The endurance limit after correction is kpsi.
MACHINE DESIGN TOPIC A short compression member with Do = 2Di is tosupport a dead load of 25 tons. The material isto be 4130 steel, WQT 1100 F. Calculate theoutside and inside diameters in terms of incheson the basis of (a) yield strength, (b) ultimatestrength.*For 4130 steel, WQT 1100 FSu = 127 ksiSy = 114 ksi*Use the following Safety FactorsNu = 4Ny = 2
Only mechanical engineering experts can do best. Subject deformable
For the drawing operation of Problem 3 (Cup Drawing), the tensile strength of the sheet metal (low-carbon steel) = 300 MPa and yield strength = 175 MPa. The die corner radius = 5 mm. Determine: a. the drawing force and, b. the blank-holding force blank diameter =150mm punch diameter= 100mm Equations used Db F = = πD,₁t (TS) (D₂₂ - 0.7) Dp F₁ = 0.015Yπ{D² – (D₂ + 2.2t + 2Ra)
Please answer in this format. Sketch: Given: Required: Solution: (Please answer in detailed (step by step). Indicate labels on what you are doing/performing, for example what formula is used) A torque To is transmitted between two flanged shafts by means of four 20-mm bolts. diameter of the bolt circle is 2=150mm. If the allowable shear stress in the bolts is 90 Mpa, what is the maximum permissible torque? Disregard friction between between flanges. The To
4. Determine the design stress for bolts in a cylinder cover where the load is fluctuating due to gas pressure. The maximum load on the bolt is 50 kN and the minimum is 30 kN. The load is unpredict- able and factor of safety is 3. The surface of the bolt is hot rolled and the suface finish factor is 0.9. During a simple tension test and rotating beam test on ductile materials (40 C 8 steel annealed), the following results were obtained : Diameter of specimen =12.5 mm; Yield strength= 240 MPa; Ultimate strength= 450 MPa; Endurance limit = 180 MPa. [Ans. 65.4 MPa]
3) The machine component from problem 2 (bar with hole and notches) undergoes variable loading from 42,500N to 45,000N. The part is made from 6061-T6 aluminum (S_u = 310 MPa and S_y = 275 MPa). The machined part requires a reliability of 95%. The large size results in a gradient strength factor of c_G=0.8 (see note c in Table 8.1). Calculate the safety factor. If the safety factor is less than one (i.e., shaft fails), find the number of cycles to failure.
450 mm long a ISI 1020 Steel long is subjected to a tensile load of 55 kilo Newton the allowable tensile stress is 140 mega pascal and the allowable total elongation is not to exit 0.2 mm calculate the required rod diameter the proportional limit is 175 megapascal
The engineering stress-engineering strain tensile curve for a stainless steel type 304 alloy is shown. Calculate the constants K and n for the true stress and true strain curve before necking (or = K (&)"). Engineering Stress (MPa) 1000 900- 800- 700- 600- 500- 400- 300- 200- 100- of 0.0 02 0.4 Enginering Strain (mm/mm) 0.6 0.8 1.0
A gauge # 10 HSLA steel for an automotive application has a Young’s modulus of 200 GPa, a yield strength of 370 MPa and a ultimate tensile strength of 440 MPa. What is the punch force needed to punch a square hole with a side length of 20 mm on this HSLA steel? Show your work.

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