19.) A tensile test was used to test certain material. Thetest specimen has the following dimensions: originallength = 2 in original cross-sectional area = 0.2 in^2.During the test the specimen yields under a load of2000 lb. The corresponding length = 2.00125 in. Themodulus of elasticity isA 16x10^6 lb/in2B16x10^6C 16x10^6 MPaD 6.25x10^-4

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Answered: A tensile test was used to test certain…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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In a Torsion test done, the following data were collected: the radius of the specimen was 3mm and the gauge length 76.2mm. During the elastic zone: T1-0. 01N.m. 01-14.760, T2-17. 13N.m, and 02-36.910. The modulus of rigidity be equal to:
Specimen (Rebar) Original Length Length when it was clamped Diameter (mm) Internal Diameter (mm) External 1 300 mm 163mm 10 15.030 2 300 mm 180 mm 10.020 14.386 3 300 mm 197mm 9.40 15.028 Dimension of Specimen Specimen A0 P max Tensile strength Modulus of elasaticity Percent Elongation 1 474 N 179.381 2.776 MPa 19.76 MPa 13.4% 2 475 N 159.070 2.895 MPa 18.74 MPa 16.67% 3 485 N 179.381 2.706 MPa 20.058 Mpa 13.4% Result of testing Observation What is the possible discussion of these tablesP.S THIS IS NOT GRADED, ITS JUST EXAMPLES
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The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.
(d) Following experimental data (TableQ1b) has obtained from the torsion test for the specimen dimension given in Table Q1a. Determine the material of a circular bar. (Take the material Poisson's Ratio as 0.32) Table Q1a Specimen Dimensions Dimensions Material Diameter (mm) 6 Length (mm) 77.15 TableQ1b Experimental Results from Torsion test Angular Deflection Degree Radian Torque/Nm 0.5 0.008727 0.06 1 0.017453 0.47 1.5 0.02618 0.76 2 0.034907 1.01 2.5 0.043633 1.32 3 0.05236 1.65 3.5 0.061087 1.99 4 0.069813 2.32 4.5 0.07854 2.66 5 0.087267 3.00 5.5 0.095993 3.33 6 0.10472 3.64 10 0.174533 5.92 20 0.349066 7.74 30 0.523599 8.07 40 0.698132 8.17 50 0.872665 7.93 60 1.047198 8.10 70 1.221731 8.2 80 1.396264 8.4 90 1.570797 8.24 100 1.74533 8.7 110 1.919863 8.7 120 2.094396 8.7 180 3.141594 9.02 240 4.188792 9.11 300 5.23599 9.48 360 6.283188 9.51 420 7.330386 9.71
Force P and length change AL data are given in table below for the initial portion of a tension test on 7075-T651 Al alloy. The diameter before testing was 9.07 mm., and the gage length Linitial for t length change measurement was 50.8 mm. What tension force is required to cause yielding in a bar of the same material but with a diameter of 20 mm? P, kN AL mm 7.22 0.0839 14.34 0.1636 21.06 26.8 31.7 34.1 35.0 0.241 0.308 0.380 0.484 0.614 36.0 0.924 36.5 1.279 36.9 37.2 1.622 1.994
Problem 2: A specimen of steel having an initial diameter of 0.503 in was tested in tension using a gauge length of 2 inches. The following data were obtained for the tension. Plot the stress strain data and determine the modulus of elasticity, and the yield strength of the material. Elastic State Load P Ibf Elongation in 1 000 0.0004 2 000 0.0006 3 000 0.0010 4 000 0.0013 7 000 0.0023 8 400 0.0028 8 800 0.0036 9 200 0.0089
Recording Help Stress (MPa) 600 500- 400- 300 200 100- 0 0.00 Tell me what you Exercise 2 Stress (MPa) 0.04 500 400 300 200- 100 0.000 0.002 0.004 0.006 Strain 0.08 Strain 0.12 0.16 0.20 Consider a cylindrical specimen of a steel alloy 10.0 mm in tension. Determine, its elongation when a load of 20,000 N is applied.
we are to find the sheer strain, sheer stress and modulus of rigidity. table,specimen length,gauge length and diameter are given. specimen length= 140mm gauge length= 77.09mm diameter= 5mm
A cylindrical specimen of 1018 steel having a diameter of 6.35 mm and a gauge length of38.1 mm is pulled in tension. Use the load-elongation characteristics tabulated below. Compute the modulus of elasticity and the approximate ductility, in percent elongation?
1. A cylindrical specimen of a metal object with a radius of 3.8E-2 m and a gauge length of 20.31 mm is pulled in tension. Use the load-elongation characteristics tabulated below to answer the following questions; Load Length (N) (mm) 20.31 20.38 12 20.45 18 20.51 24 20.55 30 20.61 36 20.64 42.8 20.68 48.9 20.72 55.2 20.76 60 20.79 65.8 20.84 70.7 20.87 77.3 20.93 83.1 20.98 88.6 22.15 91.58 23.24 91.68 25.41 0 6 Change in length Length (x10-2 m) (m) Computed strain Computed stress (N/m²) (a) Compute the cross-sectional area of brass. (3
Q1: A specimen made from Titanium with diameter 4 mm subjected to force of 2500 N. The specimen extended by 0.422 mm. If the young modulus is 107 GPa. Find the gauge length of specimen.

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