Q The one line Dingrum of a power System By the one line. Dingrumvee phase power ad Line -Line rating are given below. G. SOMVA, 22 kV, x = 24% -G2: 68.85MVA, 21 kv, x = 225 T: 90 MVA, 24/220kv, X = 1% -T2: 80 μVA, 20/220kv, x = 6% Line! 12122 Line: 492 Line ! 50 π Load: 10 μvar, Capacitor. Draw an impedance diag rem in Find matrix. Per unit and choose 20kv, 100MVA, base. Vb Sb G Te Tz LI +3E+G2 LL L3 load

Q The one line Dingrum of a power System By the one line. Dingrumvee phase power ad Line -Line rating are given below. G. SOMVA, 22 kV, x = 24% -G2: 68.85MVA, 21 kv, x = 225 T: 90 MVA, 24/220kv, X = 1% -T2: 80 μVA, 20/220kv, x = 6% Line! 12122 Line: 492 Line ! 50 π Load: 10 μvar, Capacitor. Draw an impedance diag rem in Find matrix. Per unit and choose 20kv, 100MVA, base. Vb Sb G Te Tz LI +3E+G2 LL L3 load

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.49P: Consider the single-Line diagram of a power system shown in Figure 3.42 with equipment ratings...

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Problem 1 - Series en Parallel AC networks [19] Look at the circuit in Figure 1 and determine the following: (a) Total Admittance. (b) Total Impedance. (c) Total Current (l:). (d) Current (I1) through impedance Z2. (e) Current (12) through impedance Z3. (f) Current (I3) through impedance Z4. (g) Is this an inductive or capacitive circuit? A. B Zs 220V;50HZ Figure 1 (h) Voltage across Z1. (i) Voltage across A and B. G) Voltage across Zs. Z1 = 3 + j5 ohm Z2 = 10 + jo ohm Z3 = 5 + j15 ohm Z4 = 10 – j30 ohm Zs = 20 – j30 ohm Admittance and Impedance in rectangular notation. All currents and voltage in polar notation. Take voltage as reference.
In the following network, the voltage magnitudes at all buses are equal to 1 p.u., the voltage phase angles are very small, and the line resistances are negligible. All the line reactances are equal to j1 p.u. (1) (2. P₂ = 0.1 p.u. P3 = 0.2 p.u. The voltage phase angle 83 in radian at bus 3 is (Assume one of the generator bus as slack bus and sin-¹ (0.1) = 0.1 rad) (a) -0.1 (b) -0.2 (c) 0.1 (d) 0
2. The one-line diagram of a three-phase power system is as shown in the figure below. Impedances are marked in per unit on a 100-MVA, 400-kV base. The load at bus 2 is S2 = 15.93 MW-j33.4 Mvar, and at bus 3 is S3 = 77 MW +j14 Mvar. It is required to hold the voltage at bus 3 at 4006 0 kV. Working in per unit, determine the voltage at buses 2 and 1. V3 j0.5 pu V₂ S₂ j0.4 pu S3
Three single-phase distribution transformers, each rated for 18 kVA, 20000/220 volts, are connected in a Dy three-phase bank. For convenience, at the factory, the OCT and the SCT were per- formed as per standards with the whole three-phase bank already connected and the measured values were as follows: Vline 381.051V, line 1.78436A, P30 = 372.414 W. Vline = 5656.85 V, Iline = 1.55885 A, P30 = 2160 W. Three phase bank of single phase transformer on a utility pole. 37.5 K (a) Find the single phase equivalent circuit referred to the low volt- age side. (b) Find the transformer regulation at the rated load and voltage and a power factor of 0.45 lagging (Neglect the excitation current). (c) Using the "load" model, what is the approximate transformer- bank's efficiency, n, under these conditions of load? (a) R2 X=2 Rsc=mXsc = mS (b) Vreg= (c) n = %
T 2 (3 T₂ (4) Machine 1 FLY Machine 2 Krossy 147 YA For the three-phase power system with single-line diagram, equipment ratings and per-unit reactances are given as follows: Machines 1 and 2: 120 MVA, 10.5 kV, X = X2 = 0.2, X₁ = 0.03, X = 0.03; Transformers 1 and 2: 120 MVA, 11D/115Y kV, X₁= X2 = X0 = 0.05. Select a base of 120 MVA, 115 kV for the transmission line. On that base, the series reactances of the line are X1 X2 = 0.3 and Xo = 2X1 per unit. With a nominal system voltage of 115 kV at bus 3, machine 2 is operating as a motor drawing 40 MVA at 0.8 power factor lagging. Compute the fault current for single-line-to-ground fault at bus 3
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Equipment ratings and per-unit reactances for the system shown in the below figure are given as follows: Synchronous generators: GI 100 MVA 25 kV X1 = X2 = 0.2 Xo = 0.05 G2 100 MVA 13.8 kV X = X2 = 0.2 Xo =0.05 Transformers: TI 100 MVA 25/230 kV X = X2 = X, = 0.05 T2 100 MVA 13.8/230 kV X = X2 = Xo = 0.05 Transmission lines: TL12 100 MVA 230 kV X = X2 = 0.1 Xo =0.3 TL13 100 MVA 230 kV X = X2 = 0.1 Xo = 0.3 %3D TL23 100 MVA 230 kV X = X2 = 0.1 Xo = 0.3 %3D Using a 100-MVA, 230-kV base for the transmission lines, draw the per-unit sequene networks and reduce them to their Thévenin equivalents, “looking in" at bus 3. Neglect A-Y phase shifts. Compute the fault currents for a bolted three-phase fault at bus 3. 2 T2 b T1 TL12 to G1 G2 TL13 TL23 j0,03 j0,03 3
2) The power system consists of generators, motors, transformers, and transmission lines. The ratings are as follows: G1: 3-phase generator 25 MVA, 11 KV, X = 20% M1: 3-phase motor M2: 3-phase motor T1:3 single phase transformers T2: 3-phase transformer Line: 15 MVA, 13 KV, X = 25% 7.5 MVA, 13 KV, X = 25% Single phase transformer rating 30 MVA, 6.9/69 KV X = 10% Three phase transformer rating 30 MVA, 13.8/69 KV X = 10% Χ - 50 Ω = Τι G₁ 2. Line Figure 1. 3 T2 Σ M₁ Δι M2 Find the reactance (X) in p.u. units, given the base value of 25 MVA, 11 KV.
Problem 1 The single-line diagram of a three-phase power system is shown in the below figure. Equipment ratings are given as follows: Synchronous generators: GI 1000 MVA 15 kV X - X2 - 0.18, Xo = 0.07 per unit G2 1000 MVA 15 kV X = X = 0.20, Xo = 0.10 per unit G3 500 MVA 13.8 kV x = X, = 0.15, X, = 0.05 per unit G4 750 MVA 13.8 kV X = 0.30, X2 = 0.40, X, = 0.10 per unit Transformers: TI 1000 MVA 15 kV A/765 kV Y X = 0.10 per unit T2 1000 MVA 15 kV A/765 kVY X= 0.10 per unit T3 500 MVA 15 kV Y/765 kV Y X = 0.12 per unit T4 750 MVA 15 kV Y/765 kVY X = 0.11 per unit T3 Line 1-3 Line 1-2 2 Line 2-3 Transmission lines: 1-2 765 kV X¡ = 50 Q, X, = 150 N 1-3 765 kV X = 40 N, X, = 100 . 2-3 765 kV X1 = 40 Q, X, = 100 N The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as a base. Calculate the zero-, positive-, and negative-sequence reactance using a 1000- MVA, 765-kV base in the zone of line 1-2. Neglect the A-Y transformer phase shifts. 石。
Figure below shows the one line diagram of a 3-o system. By selecting a common base of 100 MVA and 22 KV on the generator side, draw an impedance diagram showing all impedances including the load impedance in per unit. The data are given as follows: G: 100 MVA, 22 KV, X= 0.18 pu 22/220 KV, X= 0.1 pu TR1: 50 MVA, TR2: 40 MVA, 220/11 KV, X=0.06 pu Load 1: 50 MVA, 0.8 pf lag Load 2: 50 MVA, 0.8 pf lead If volt at bus 4 equal 11 KV constant value : calculate i) volt at bus 1 ii) EMF (Eg) of generator ii) Transmission line current TR1 TR2 ZTL=j80 2 G1 3. 4 Load 1 Load 2
High voltage engineering subject
2. Draw the reactance diagram for the power system shown in Figure 2. Neglect the resistance and use a base of 50 MVA and 13.8 kV on generator G1. G1 : 20 MVA, 13.8 kV, X"= 20% G2 : 30 MVA, 18.0 kV, X"= 20% G3 :30 MVA, 20.0 kV, X"= 20% T1:25 MVA, 220/13.8 kV, X = 10% T2: 3 single phase unit each rated 10 MVA, 127/18 kV, X = 10% T3: 35 MVA, 220/22 kV, X = 10% Determine the new values of per unit reactance of G1, T1, transmission line 1,transmission line 2, T2, G2, T3 and G3. Line I Line 2 j80 2 j100 2 ele T Vele G. Fig.2: One line diagram of the system