Please answer a to g. A superheterodyne receiver is to tune the range 88.1MHz to 107.1MHz. The RF circuitinductance is 1μH. Low side injection is used.a. Calculate the minimum capacitance of the variable capacitor in the RF circuitANSWER: 2.208pFb. Calculate the RF circuit capacitance tuning ratio ANSWER: 1.4778c. If the receiver has a single converter stage and IF of 800kHz, calculate the capacitancetuning ratio of the local oscillator ANSWER: 1.483d. If the maximum capacitance of the variable capacitor of the local oscillator is 0.2pF,calculate the minimum capacitance ANSWER: 0.135pFe. If the receiver has a single converter stage and IF of 800kHz, calculate the imagefrequency of 103.7MHz ANSWER: 102.IMHzf. Calculate the IFRR (in dB) of (e) if Q of the preselector is 50 ANSWER: 5.338dBg. To increase IFRR of (e) to 40dB, double conversion is used. What must be the frequencyof the 1st IF? ANSWER: 30.373 MHz

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Answered: A superheterodyne receiver is to tune…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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n CRO, the pulse voltage waveform is displayed in Figure below. The 'time/cm’ switch is on 2 ms/cm and the 'volts/cm’ switch is on 10 V/cm. Calculate (a) the periodic time, (b) the peak to peak voltage, (c) the R.M.S voltage The periodic time is = The peak to peak voltage is = The R.M.S voltage is =

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