Determine lx for the following circuit using nodal analysis when Va=21 V, Vb=9 V, R4-19 Q2 and R5-10 2. R1-15 2, R2=19 2, R3-18 V2 R1 Va+ Your Answer: R3 Ix R5 2222 R2 R4 Vb Answer units
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- PLS PLS SHOW COMPLETE SOLUTION AND WRITE LEGIBLY. DRAW CIRCUIT DIAGRAM. PLS PLSS SHOWS HOW ALL THE EQUATIONS ARE REDUCED TO NEEDED.PLS PLS SHOW COMPLETE SOLUTION AND WRITE LEGIBLY. DRAW CIRCUIT DIAGRAM. PLS PLSS SHOW HOW THE EQUATIONS REDUCED TO NEEDED.Question 1 R4 V2 R3 R1 R2 For the above circuit, select ALL the extraordinary nodes that are part of a supernode. If there are none then select NONE Note: a quas-supernode is not a supernode. P Type here to search
- In the given figure, use the principle of superposition to determine the component of the current/through R3 due to V52. Assume R- 10 02, R2=80, R3-13 0, R4 R5-160, and VS1 VS2=750 V. = ww R₁ VS1 VS2 R₁ www ww ww R₁ R3 R₂ ww The component of the current/through R3 due to V52 is AThe impedances of the bridge are as follows, Z1: A resistor R1 in parallel with C1. Both R1 and C1 are known Z2: R2 , an adjustable resistor of known value Z3 : An adjustable resistor R3 in parallel with an adjustable C3 where values of R3 and C3 are known. Z4: A capacitor C4 of known value in series with R4 an unknown resistor Determine the real and imaginary parts expressions for the balance conditionUsing the circuit below, complete the table while showing your solutions and circuit simplifications. C1 = 1x10 HE F C3 =3x10¬°F H -6 F C5 = 5x10 C6 4x10¬º F = -6 2x10 ° F = C2 : C4 -6 = 6x10° F %3D 9x10-6 F = C9 Cg C, = 7x10 -6 F -6 = 8x10 F Ceq = Charge (C) Voltage (V) Q1 = Q2 = Q3 = Q4 = Q5 = Q6 = Q7 = Q8 = Qg = QT = V, = V2 = | V3 = V4 = V5 = V6 = V7 = V8 = V9 = AV = 24 V
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