▸ A 2.4 KVA, 2400/240 V 50 Hz step down ▸ transformer has the following parameters X2 R₁ = 1.52, X₁ = 2.52, R₂ = 0.022, X₂ =0.03, Rc1 = σκΩ, Xmi = 8ΚΩ ▸ It is operating at 80% of its rated load at unity power factor. Using the exact equivalent circuit of the transformer determine its efficiency.

▸ A 2.4 KVA, 2400/240 V 50 Hz step down ▸ transformer has the following parameters X2 R₁ = 1.52, X₁ = 2.52, R₂ = 0.022, X₂ =0.03, Rc1 = σκΩ, Xmi = 8ΚΩ ▸ It is operating at 80% of its rated load at unity power factor. Using the exact equivalent circuit of the transformer determine its efficiency.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.10P: A single-phase step-down transformer is rated 13MVA,66kV/11.5kV. With the 11.5 kV winding...

See similar textbooks

Similar questions

Consider an ideal transformer with N1=3000andN2=1000 turns. Let winding 1 be connected to a source whose voltage is e1(t)=100(1| t |)volts for 1t1ande1(t)=0 for | t |1 second. A2- farad capacitor is connected across winding 2. Sketch e1(t),e2(t),i1(t),andi2(t) versus time t.
For an ideal 2-winding transformer, an impedance Z2 connected across winding 2 (secondary) is referred to winding 1 (primary) by multiplying Z2 by (a) The turns ratio (N1/N2) (b) The square of the turns ratio (N1/N2)2 (c) The cubed turns ratio (N1/N2)3
For a short-circuit test on a 2-winding transformer, with one winding shorted, can you apply the rated voltage on the other winding? (a) Yes (b) No
The symbol shown is a(n) a. iron core transformer. b. auto transformer. c. current transformer. d. air core transformer.
An ideal transformer has no real or reactive power loss. (a) True (b) False
For an ideal transformer, the efficiency is (a) 0 (b) 100 (c) 50
A single-phase step-down transformer is rated 13MVA,66kV/11.5kV. With the 11.5 kV winding short-circuited, rated current flows when the voltage applied to the primary is 5.5 kV. The power input is read as 100 kW. Determine Req1andXeq1 in ohms referred to the high-voltage winding.
A single-phase, 50-kVA,2400/240-V,60-Hz distribution transformer has the following parameters: Resistance of the 2400-V winding: R1=0.75 Resistance of the 240-V winding: R2=0.0075 Leakage reactance of the 2400-V winding: X1=1.0 Leakage reactance of the 240-V winding: X2=0.01 Exciting admittance on the 240-V side =0.003j0.02S (a) Draw the equivalent circuit referred to the high-voltage side of the transformer. (b) Draw the equivalent circuit referred to the low-voltage side of the transformer. Show the numerical values of impedances on the equivalent circuits.
Topic- basic & const.
Which of the following statements is true about an ideal transformer? O It changes the magnitude of DC signals. O It converts DC signals into AC signals. O It changes the magnitude of AC signals. O It converts AC signals into DC signals.
SOLVE STEP BY STEP IN DIGITAL FORMAT XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX 2. A transformer with a 10/1 turns ratio has a maximum flux density of 60,000 lines/in2, when the primary winding is connected to a 2300 V power supply at 60 cps. What will be the maximum flux density if the secondary is connected to a 115 volt supply at 25 cps with the primary open?
How does the coupling factor affect the primary and secondary voltages? For example if the turns ratio in my transformer is 1:2 and the Vin is 10V, the voltage on the primary side is 10V and the voltage on the secondary side is 20V when the coupling factor (k) is 1. What will the primary and secondary voltages be if the coupling factor becomes 0.5?