Find the Norton equivalent current IN that drives R4 when E-12 V, R1=9, R2=1 R3-31 and R4-10. Ш R1 R3 a b w w R2 4 R4 Your Answer: Answer units
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- Please solve this using nodes and branches method (Kirchhoff's laws). I need the equations for junction rule and loop rule. 675 2 900 N 450 2 12 v 250 N 1000 2PLS PLS SHOW COMPLETE SOLUTION AND WRITE LEGIBLY. DRAW CIRCUIT DIAGRAM. PLS PLSS SHOW HOW THE EQUATIONS REDUCED TO NEEDED.For R1-8, R2=17, 11=24 A & K1=4 in the shown circuit, Find the Norton equivalents at terminals a-b of the circuit shown in figure: (Rth may be -ve due to the presence of the dependent source) Klio R1 ww -o a Il o b IN(Norton current in ampere)= a. 14.857142857143 O b.-7.4285714285714 c. 7.4285714285714 O d. 22.285714285714 Rth (in ohm)= a.-21 O b. 21 c.-42 d. 8.4 www R2
- 4. Use the diagram to answer the questions that follow. 4. J1 13 J2 R3 R2 R5 15 L1 14 R4 L2 L3 81. In 82 R1 D 11 a. Write the junction rules for J1 and J2 according to the circuit diagram in terms of the currents Ij thru I5 J1: J2: b. Write the loop rules for L1, L2, and L3 (Loop 1,2, and 3) according to the diagram. Go Clockwise as shown. L1: L2:For R1=55, R2=D125, R33D135, R4=15, R5=40, R63D90 and V1=4 V in the shown figure, use circuit reduction and current/voltage division rules to calculate the following: R6 R1 R5 R3 R2 V1 V2 R4 V13= V2=Electrical Engineering 5. Solve the following system by any valid method: 3r1 + 12 + x3 + x4 = 0 5x1 - 12 + 13 – 14 = 0.
- Use A-Y/ Y-A Transformation to solve for the (a) total resistance in terminals op (Rop) (b) total current. Voltage at terminal fe (Vfe) is 250 V. Show complete solution and redraw your transformations. 250 -W- 100 -25 100 20 100 500 E50 10 100 gniue 75Draw the AC equivalent circuit. Extract the laws (Av, Ai, Zi). and Calculate Zi, Zo Av for the circuit below C7 OTE Vi 1uF 39k Hei 9V R4(2) 22k C5 10uF 1.8k C1 Vo HE 1uF Q2 BC237 B=80 Note: the solution to the question step by step by handCircuit theory