Q.4) [10 points] The circuit shown in Figure 4 is used to make a simple low-pass filter. An important part of choosing the appropriate value of C is to determine the highest frequency to be passed and then choose a value of C such that the output voltage is 1/√2 times the magnitude of the input at that frequency. What value of C makes this a low-pass filter for frequencies from 0 Hz to 1000 Hz? 10 ΚΩ www + Vin(t) Figure 4 + C Vout(t)
Q.4) [10 points] The circuit shown in Figure 4 is used to make a simple low-pass filter. An important part of choosing the appropriate value of C is to determine the highest frequency to be passed and then choose a value of C such that the output voltage is 1/√2 times the magnitude of the input at that frequency. What value of C makes this a low-pass filter for frequencies from 0 Hz to 1000 Hz? 10 ΚΩ www + Vin(t) Figure 4 + C Vout(t)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![Q.4)
[10 points]
The circuit shown in Figure 4 is used to make a simple low-pass filter. An
important part of choosing the appropriate value of C is to determine the highest frequency to be
passed and then choose a value of C such that the output voltage is 1/√2 times the magnitude of
the input at that frequency. What value of C makes this a low-pass filter for frequencies from
0 Hz to 1000 Hz?
10 ΚΩ
www
+
Vin(t)
Figure 4
+
C
Vout(t)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a55d95a-1f6d-4e44-9b81-73fca9765ab6%2F2f81ea9d-5c01-4141-a706-ae3ffcabfada%2Fi7uax1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q.4)
[10 points]
The circuit shown in Figure 4 is used to make a simple low-pass filter. An
important part of choosing the appropriate value of C is to determine the highest frequency to be
passed and then choose a value of C such that the output voltage is 1/√2 times the magnitude of
the input at that frequency. What value of C makes this a low-pass filter for frequencies from
0 Hz to 1000 Hz?
10 ΚΩ
www
+
Vin(t)
Figure 4
+
C
Vout(t)
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