Calculate the value of VX in the following circuit, when the value for the sources and resistors are the following: V1=34 Volts V2=3.1 Volts R1=460 Ohms R2=275 Ohms R3=960 Ohms R4=846 Ohms Vx + w R3 R2 R4 V1 R1 V2
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can you solve it using 3 decimals in your calculations and 2 in your answer
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- Based on Figures la,1b and 1c and RLC elements, write a discussion on voltage-current relations and power factor. Im A Im A Im A V Re Re Re Figure la. Figure 1b. Figure 1c.I need help understanding this question, what does this question is talking aboutdhjdhjhdjdhjfhfjdbfejfheidadadisfdfodf,fdhjfhdfj The equivalent resistance of three resistors A, B and C connected in parallel is 1.5 ohms. If A is thrice of B and C is 1/4 of B. Find the equivalent resistance when the three of them are connected in series? dhsfhfeirwdiwudwiwui
- Given the zener voltage at 9V and the zener power at 1W, what is the range of allowable values of Iz (operating values). Choices: 0.11A 22mA to 89mA 9A 0.11A to 9A Plss show complete solutionIn the figure below, what is the potential difference Va-V, between points d and c if %₁-5.0 V. 82- 1.8 V. R₁ R₂ = 140, and R3-5.2 Q, and the batteries are ideal? Number i -11341 Units V #1*C -Q (A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to C1 and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 [-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge[net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy]: Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-왕-용 (True, False) = 0 conservation of energy +V - = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Q3 follow from above three equations as C1(C2 + C3) V Q2 = Ci + C2 + C3 C1 C3 Ci + C2 + C3 Q1 = Q3 = V, (True, False) C1 + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = C1(C2+C3) v which implies an equivalent capacitance of Qtot…
- Determine the equivalent resistance across the terminals if R1 = 2R2 = 3R3 = 4R4.etc. and R11 = 3 ohms. R. Ry RI R.Determine the voltage V1 in Volts for the following circuit with component values ISRC = 1.6 mA, VSRC = 6 V, R1 = 2.3 k2, R2 = 3.5 kQ, and R3 = 1.3 kQ. Vsrc + R1 w R2 w Isrc V1 + R3 www 11 12 4 13Resistors Circuits I Each of the circuits below consists of a battery and several resistors. Several of the voltages, currents, and resistances are indicated. Use both of Kirchoff's Laws and Ohm's Law to determine as many of the other voltages, currents, and resistances as possible.