Problem 1The single-line diagram of a three-phase power system is shown in the below figure. Equipmentratings are given as follows:Synchronous generators:GI 1000 MVA15 kVX - X2 - 0.18, Xo = 0.07 per unitG2 1000 MVA15 kVX = X = 0.20, Xo = 0.10 per unitG3 500 MVA13.8 kVx = X, = 0.15, X, = 0.05 per unitG4 750 MVA13.8 kVX = 0.30, X2 = 0.40, X, = 0.10 per unitTransformers:TI 1000 MVA15 kV A/765 kV YX = 0.10 per unitT2 1000 MVA15 kV A/765 kVYX= 0.10 per unitT3 500 MVA15 kV Y/765 kV YX = 0.12 per unitT4 750 MVA15 kV Y/765 kVYX = 0.11 per unitT3Line 1-3Line 1-22Line 2-3Transmission lines:1-2 765 kVX¡ = 50 Q, X, = 150 N1-3 765 kVX = 40 N, X, = 100 .2-3 765 kVX1 = 40 Q, X, = 100 NThe inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3ratings as a base. Calculate the zero-, positive-, and negative-sequence reactance using a 1000-MVA, 765-kV base in the zone of line 1-2. Neglect the A-Y transformer phase shifts.石。

Given base parameters for zone 1-2 MVAb = 1000 MVA KVb =765 kV to determine positive negative and…

The single-line diagram of a three-phase power system is shown in the below figure. Equipment ratings are given as follows: Synchronous generators: GI 1000 MVA x - X2 - 0.18, Xo -0.07 per unit X - X2 - 0.20, Xo =0.10 per unit X- X, -0.15, Xg- 0.05 per unit 15 kV G2 1000 MVA 15 kV G3 500 MVA 13.8 kV G4 750 MVA 13.8 kV X = 0.30, X2 - 0.40, Xo = 0.10 per unit Transformers: 15 kV A/765 kV Y X- 0.10 per unit X - 0.10 per unit X - 0.12 per unit X - 0.11 per unit TI 1000 MVA T2 1000 MVA 15 kV A/765 kV Y T3 500 MVA 15 kV Y/765 kV Y T4 750 MVA 15 kV Y/765 kV Y 3 T, Line 1-3 Line 1-2 Line 2-3 Transmission lines: 1-2 765 kV X = 50 2, Xo -150 N 1-3 765 kV X1 = 40 2, X, - 100 2 2-3 765 kV X = 40 2, X, = 100 2 The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as a base. Calculate the zero-, positive-, and negative-sequence reactance using a 1000- MVĀ, 765-kV base in the zone of line 1-2. Neglect the A-Y transformer phase shifts.

The single-line diagram of a three-phase power system is shown in the below figure. Equipment ratings are given as follows: Synchronous generators: GI 1000 MVA x - X2 - 0.18, Xo -0.07 per unit X - X2 - 0.20, Xo =0.10 per unit X- X, -0.15, Xg- 0.05 per unit 15 kV G2 1000 MVA 15 kV G3 500 MVA 13.8 kV G4 750 MVA 13.8 kV X = 0.30, X2 - 0.40, Xo = 0.10 per unit Transformers: 15 kV A/765 kV Y X- 0.10 per unit X - 0.10 per unit X - 0.12 per unit X - 0.11 per unit TI 1000 MVA T2 1000 MVA 15 kV A/765 kV Y T3 500 MVA 15 kV Y/765 kV Y T4 750 MVA 15 kV Y/765 kV Y 3 T, Line 1-3 Line 1-2 Line 2-3 Transmission lines: 1-2 765 kV X = 50 2, Xo -150 N 1-3 765 kV X1 = 40 2, X, - 100 2 2-3 765 kV X = 40 2, X, = 100 2 The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3 ratings as a base. Calculate the zero-, positive-, and negative-sequence reactance using a 1000- MVĀ, 765-kV base in the zone of line 1-2. Neglect the A-Y transformer phase shifts.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Synchronous Generator

In comparison to an asynchronous generator, it is a machine where the rotor speed is equal to the rotating magnetic field produced by the stator, i.e., mechanical speed is equal to the electrical speed, thus called synchronous, and not asynchronous.

Salient Pole Rotor

Salient pole rotor includes a large number of exposed poles mounted on a magnetic wheel. The construction of a bright pole is as shown in the image on the left. The proposed poles are made of metal laminations. The rotor winding is provided on these poles and is supported by pole shoes.

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Problem 1
The single-line diagram of a three-phase power system is shown in the below figure. Equipment
ratings are given as follows:
Synchronous generators:
GI 1000 MVA
15 kV
X - X2 - 0.18, Xo = 0.07 per unit
G2 1000 MVA
15 kV
X = X = 0.20, Xo = 0.10 per unit
G3 500 MVA
13.8 kV
x = X, = 0.15, X, = 0.05 per unit
G4 750 MVA
13.8 kV
X = 0.30, X2 = 0.40, X, = 0.10 per unit
Transformers:
TI 1000 MVA
15 kV A/765 kV Y
X = 0.10 per unit
T2 1000 MVA
15 kV A/765 kVY
X= 0.10 per unit
T3 500 MVA
15 kV Y/765 kV Y
X = 0.12 per unit
T4 750 MVA
15 kV Y/765 kVY
X = 0.11 per unit
T3
Line 1-3
Line 1-2
2
Line 2-3
Transmission lines:
1-2 765 kV
X¡ = 50 Q, X, = 150 N
1-3 765 kV
X = 40 N, X, = 100 .
2-3 765 kV
X1 = 40 Q, X, = 100 N
The inductor connected to Generator 3 neutral has a reactance of 0.05 per unit using generator 3
ratings as a base. Calculate the zero-, positive-, and negative-sequence reactance using a 1000-
MVA, 765-kV base in the zone of line 1-2. Neglect the A-Y transformer phase shifts.
石。

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