The second-order circuit shown below has the source voltage V,= 220 V, inductance L= 10 mH, capacitance C = 8 μF, and resistance R = 15. The initial conductor current I₁p=OA and the initial voltage of the capacitance is Vco = 0 V. The switch is closed at t = 0. The expression of the current is: Ve Select one: O a. i(t) 12.41e-22001, 2001 sin(4226t) O b. i(t) 8.63e-28501sin(3252t) Oc. i(t)=6.36e-750.sin(3455t) O d. none of these Oe. i(t)-8.42e-1250* sin(5893)

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter24: Resistive-inductive-capacitive Parallel Circuits
Section: Chapter Questions
Problem 1RQ: An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in...
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The second-order circuit shown below has the source voltage V,= 220 V, inductance L= 10 mH, capacitance C = 8 μF, and resistance R = 15. The initial conductor current I₁p=OA and the initial voltage of the capacitance is Vco = 0 V. The
switch is closed at t = 0. The expression of the current is:
Ve
Select one:
O a. i(t) 12.41e-22001,
2001 sin(4226t)
O b. i(t) 8.63e-28501sin(3252t)
Oc. i(t)=6.36e-750.sin(3455t)
O d. none of these
Oe. i(t)-8.42e-1250* sin(5893)
Transcribed Image Text:The second-order circuit shown below has the source voltage V,= 220 V, inductance L= 10 mH, capacitance C = 8 μF, and resistance R = 15. The initial conductor current I₁p=OA and the initial voltage of the capacitance is Vco = 0 V. The switch is closed at t = 0. The expression of the current is: Ve Select one: O a. i(t) 12.41e-22001, 2001 sin(4226t) O b. i(t) 8.63e-28501sin(3252t) Oc. i(t)=6.36e-750.sin(3455t) O d. none of these Oe. i(t)-8.42e-1250* sin(5893)
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