In an L-R-C series circuit, the source has a voltage ampli- tude of 120 V, R 80.0 l, and the reactance of the capacitor is 480 11. The voltage amplitude across the capacitor is 360 V a) What is the current amplitude in the circuit? b) What is the impedance? c) What two values can the reactance of the inductor have? d) For which of the two values found in part (c) is the angu- lar frequency less than the resonance angular frequency? Explain R=80 16 X₁ = 480x 160V

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Author:Robert L. Boylestad
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In an L-R-C series circuit, the source has a voltage ampli-
tude of 120 V, R 80.0 1, and the reactance of the capacitor is
480 11. The voltage amplitude across the capacitor is 360 V
a) What is the current amplitude in the circuit? b) What is the
impedance? c) What two values can the reactance of the inductor
have? d) For which of the two values found in part (c) is the angu
lar frequency less than the resonance angular frequency? Explain
R= 80
X₁ = 480x
160V
Transcribed Image Text:In an L-R-C series circuit, the source has a voltage ampli- tude of 120 V, R 80.0 1, and the reactance of the capacitor is 480 11. The voltage amplitude across the capacitor is 360 V a) What is the current amplitude in the circuit? b) What is the impedance? c) What two values can the reactance of the inductor have? d) For which of the two values found in part (c) is the angu lar frequency less than the resonance angular frequency? Explain R= 80 X₁ = 480x 160V
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