Problem # 3: A gutter beam is composed a C 6x13 channel and 2 pcs. of ¾ " x 7 steel plate whose section is shown below. The beam is overhang in the left side 3 ft. from support B. and carry a uniformly distributed load w=25 lbs/ft. including its own weight and two concentrated load P1 = 5 lbs. and P2= 10 lbs located as shown. P₂ 3/4" x 7" plate w=lb/ft CG x 13 Properties of C 6 x 13 A= 3.83 in² tw = 0.437 in bf = 2.157 in bf breadth of flange Ix = 17.4 in4 Iy = 1.05 in x = 0.514 in tf = .343 in 3 ft.. 10 ft 6 ft

Problem # 3: A gutter beam is composed a C 6x13 channel and 2 pcs. of ¾ " x 7 steel plate whose section is shown below. The beam is overhang in the left side 3 ft. from support B. and carry a uniformly distributed load w=25 lbs/ft. including its own weight and two concentrated load P1 = 5 lbs. and P2= 10 lbs located as shown. P₂ 3/4" x 7" plate w=lb/ft CG x 13 Properties of C 6 x 13 A= 3.83 in² tw = 0.437 in bf = 2.157 in bf breadth of flange Ix = 17.4 in4 Iy = 1.05 in x = 0.514 in tf = .343 in 3 ft.. 10 ft 6 ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

plz, solve all the parts of this problem. Plz, use ACI Code. Reinforced Concrete Design-1 A fixed ended beam with span length of 24′ and cross-section of 15ʺ x 24ʺ is subjected to uniformly distributed load is shown in figure 1. Unform service dead load is 1k/ft and uniform service live load is 1.4 k/ft. Taking ?c = 3??? and ?y = 40???, a) Detail the reinforcement using #6 bar only, and also curtail the steel ensuring development length requirements. b) Show all your calculations in the form of neat and clean drafting.
1. A rectangular beam has b = 300mm, d = 500mm, AS = 6 – 36mm diameter bars, fc' = 28.6 MPa, fy = 414 MPa. Calculate: a) depth of compression block, "a" b) fs c) Þ d) Mu
A 3m-LONG CANTILEVER BEAM IS CARRYING A UNIFORM DEADLOAD OF 20 kN/m (EXCLUDING SELFWEIGHT OF THE BEAM), AND A LIVE LOAD OF 15 kN/m. OTHER GIVEN: fc = 27.5 MPa fy = 414 MPa b = 300mm h = 600mm diameter of main reinforcements, db = 25mm diameter of transverse reinforcements, ds = 12mm use clear concrete cover of 45mm unit weight of concrete is 25kN/m3 Solve for the following: a. Reactions at the fixed support. b. Maximum FACTORED moment of the beam, Mu c. Effective depth of the beam d. As required e. No. of 25mm reinforcements required to resist Mu f. Spacing of stirrups at the critical location (d from face of the support) - use manual calculations, show your solutions.
A steel column W300 x 203 kg/m section is used as to support an aial load. A=25740mm^2 Tw = 20mm. Fy= 415 Mpa Tf = 32mm. Lu= 4m d = 340mm. Ix=5.16*10^ 8 mm^4 Iy= 1.65*10^8mm^4 E = 200GPA k = 1.0 Sidesway is prevented. Determine the ultimate design capacity of Column using NSCP 2015. Use Phi= 0.9. 7718.11kN C. 8575.88 kN 333.17 kN D. 20356.06kN
The beam is simply supported on a span of 6 m and carries a load of 18 KN/m. Use ACI Specifications withfc’ = 17.2 MPa, fs = 124 MPa, n = 12, d’ = 65 mm, and ?concrete = 23.54 KN/m3.(a) service moment (f) use b = 250 mm, d = Answer (round down to nearest 25 mm) + 50 mm(b) fc to take care of dead load(c) k (g) h (h) dead load (i) total load(d) j (j) recompute service moment (k) check effective depth(e) R (l) use 28mmɸ for As (m) check main bar clear spacing
Design a square base plate to support 10 mm thick pipe column with an inside diameter of 300 mm. The base plate minimum dimension is 500 mm. To design plate thickness, convert the circular perimeter of the pipe into an equivalent square with an area equal to the original circle. The loads are PDL = 850 kN and PLL =420 kN. Assume that the pipe is to rest on a very wide slab. Use A-50 steel and concrete fc’ = 35MPa and LRFD.
It is desired to remove the spike from the timber by applying force along its horizontal axis. An obstruction A prevents direct access, so that two forces, one 420 Ib and the other P, are applied by cables as shown. Compute the magnitude of P necessary to ensure a resultant T directed along the spike. Also find T. 3" A 5" 420 lb Answers: P = Ib T= i Ib
PROBLEM 1: A reinforced concrete beam has a simple span of 8m. It carries a concentrated factored load, Pu=200KN (40% DLcand 60%LL), at midspan. The beam is reinforced with 3D25mm. It has a width of 300mm and andepth of 400mm and 12mm stirrups. Take fc' to be 24MPA and fy=420MPA and fyt=280MPA. Use simplified calculation of Vc 1. What is the ultimate shear capacity of concrete at a section 2m from the support, KN? 2. What should be the shear capacity of web reinforcement at the section 2m from the support, KN? 3. What is the maximum spacing of web reinforcement allowed by the code (NSCP) at the section 2m from the support if the diameter of stirrups is 12mm, mm? 4. What is the required spacing of web reinforcement at the section 2m from the support if the diameter of stirrups is 12mm, mm?
Design a singly reinforced beam. Use f'c = 28 MPa, fy = 414 MPa
Calculate the factored moment strength of the slab below. If the only dead load the slab has to handle is its own self-weight, how much service live load can the slab hold? For finding this make the moment strength you calculate equal to Mu and solve for the possible live load using a factored load equation. f'c = 3000 psi, fy = 40000 psi A A -Span for design = 12'-0"– clear #8 @ 6" 0.c. Section A-A 8"
For the following plan it is required to: 1- Design all beams for flexure and shear, where they have additional 30 kN/m distributed factored load 2- Design the columns. The concrete has a strength of 30 MPa, and the yield strength of the steel is 420 MPa. Show full calculations and neat sketches. All dimensions are in m. I 03 B2 0,3 7 B1 Wu=20 kN/m2 B1
Design a monolithic concrete slab indicated below. The floor slab is to carry a service live load of 2.7KPa uniformly distributed over its surface and service dead load of (floor finish = 5 KPa). Use f'c = 21MPA, fy= 276MPa, Unit weight of concrete = 24KN/m^3. Design only details of slab along long span. 4m This slab 6m