A continuous beam is reinforced for negative moment with #6 uncoated bars. The beam has a depth of 24 inches and is normal weight concrete with fc= 5 ksi. Determine the development length of the #6 bars. Use a confinement factor equal to 1. Stirrups are #4 and cover is 1.5in.
A continuous beam is reinforced for negative moment with #6 uncoated bars. The beam has a depth of 24 inches and is normal weight concrete with fc= 5 ksi. Determine the development length of the #6 bars. Use a confinement factor equal to 1. Stirrups are #4 and cover is 1.5in.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A continuous beam is reinforced for negative moment with #6 uncoated bars. The
beam has a depth of 24 inches and is normal weight concrete with fc= 5 ksi.
Determine the development length of the #6 bars. Use a confinement factor equal
to 1. Stirrups are #4 and cover is 1.5in.
Expert Solution
Step 1
Given:
The depth of the beam is 24 in.
The value of fc’ is 5 ksi or 5000 psi.
The confinement factor is 1.
The cover is 1.5.
Step 2
The formula to calculate the development length of the bars is,
But the confinement factor,
Here, db is the diameter of the reinforcement bar, Ktr is the transverse reinforcement index, and Cb is the cover.
Step 3
Assume the yield strength of the bar is 60,000 psi.
The reinforcement location factor,
The coating factor is,
The reinforcement size factor is,
For normal-weight concrete,
The diameter of #6 bars is,
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