For the following plan it is required to: 1- Design all beams for flexure and shear, where they have additional 30 kN/m distributed factored load 2- Design the columns. The concrete has a strength of 30 MPa, and the yield strength of the steel is 420 MPa. Show full calculations and neat sketches. All dimensions are in m. I 7 B1 Wu= 20 kN/m2 B1

Q: Compute the Modulus of Rupture of the beam shown, in MPa.

A: "Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Q2 : Design the beam showing below for shear by using Ultimate Strength Design method according to…

A:

Q: simply supported beam is reinforced with 4 – 28 mm ø at the bottom and 2 – 28 mm ø at the top of the…

A: Given  fc’ = 30 MPa, fy = 415 MPa. Balanced steel ratio ρb = 0.031 Reduction factor= 0.9

Q: (3) for Normal weight Concrete, using ACI Code and recommendation for high strength concrete, to…

A: Solving first questionGiven datacompressive strength of concrete given in table findmodulus of…

Q: 14" #3 stirrup 25" 4- #11

A: Solution Given Data f'c=3500 psify=60000 psid=22 in

Q: GIVEN; A column made of 2 materials: a W 6 x15 structural steel section Page 3 encased in concrete…

A: area os  steel section  As=4.43 in2Area of concrete  AC=75 in2modular ratio…

Steel Framing

A steel frame consists of a skeleton frame structure comprising of horizontal I-beams and vertical steel columns fitted in a rectangular grid building construction to brace the floors, walls, and the roof of the building held onto the frame. Due to the implementation of this methodology, the construction of the skyscrapers was feasible.