Problem # 3: For the given beam, use 150 pcf concrete: Consider two possible load combinations: a. Calculate the factored shear (Vu) and factored moment (Mu). Draw the diagrams and report the maximum values. b. Identify the tension and compression side of the beam and the placement of the reinforcing steel for flexure at section cut A-A (at midspan). 24ft Section A-A U=1.2D +1.6L and WL = 0.75 kip/ft WD = 3.7 kip/ft + self weight From your diagrams, what are the max values? Mu= _kip-ft Vu= kip 12" U=1.4D 24"

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Problem #3: For the given beam, use 150 pcf concrete:
Consider two possible load combinations:
a. Calculate the factored shear (Vu) and factored moment (M₁). Draw the diagrams and report the maximum
values.
b. Identify the tension and compression side of the beam and the placement of the reinforcing steel for flexure
at section cut A-A (at midspan).
24ft
=
Section A-A
From your diagrams, what are the max values?
Mu
kip-ft Vu=
U=1.2D +1.6L
WL = 0.75 kip/ft
WD = 3.7 kip/ft + self weight
kip
and
| 12″
U=1.4D
24"
2
/
5
Transcribed Image Text:Problem #3: For the given beam, use 150 pcf concrete: Consider two possible load combinations: a. Calculate the factored shear (Vu) and factored moment (M₁). Draw the diagrams and report the maximum values. b. Identify the tension and compression side of the beam and the placement of the reinforcing steel for flexure at section cut A-A (at midspan). 24ft = Section A-A From your diagrams, what are the max values? Mu kip-ft Vu= U=1.2D +1.6L WL = 0.75 kip/ft WD = 3.7 kip/ft + self weight kip and | 12″ U=1.4D 24" 2 / 5
Expert Solution
Step 1

Given:

Load conditions:

U=1.2D+1.6L

U=1.4D

Loads:

WD=3.7 kip/ft + self weight

WL=0.75 kip/ft

Concrete density = 150 pcf

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