Question 81 pThe rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars ontop and 3N28 bars on bottom. The modulus of elasticity are Ec=23,500MPa and Es = 200,000MPa. Dead load is18KN/m and live load is 12KN/m.f'c = 25MPa800TE730N12 ligs (fsv.t-500MPa)Ast = 3N28350Span = 10mFigure 3Calculate the concrete stresses in tension and compression of the reinforcement concrete beam shown inFigure 3.Compression concrete stressChoose ]Tension Concrete stressChoose]

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The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec=23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f'=25MPa 730 N12 ligs (fsv.t-500MPa) Ast = 3N28 350 ↓↓↓ Span = 10m Figure 3 Calculate the concrete stresses in tension and compression of the reinforcement concrete beam shown in Figure 3. Compression concrete stress [Choose ] Tension Concrete stress [Choose ] 800

The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec=23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f'=25MPa 730 N12 ligs (fsv.t-500MPa) Ast = 3N28 350 ↓↓↓ Span = 10m Figure 3 Calculate the concrete stresses in tension and compression of the reinforcement concrete beam shown in Figure 3. Compression concrete stress [Choose ] Tension Concrete stress [Choose ] 800

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter9: Composite Construction

Section: Chapter Questions

Problem 9.1.3P

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Composite Construction

Composite construction is the construction of structures in which two or more materials are used. Regarding structural engineering, composite construction is a construction where two materials are bound together in a technical manner such that both the materials act as a single unit to carry and transfer the load. The motives of composite construction are to increase the structural strength, make structures more aesthetic, and provide a sustainable environment.

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The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f' = 25MPa 800 IDE 730 N12 ligs (fsv.f-500MPa) Ast = 3N28 350 Span = 10m Figure 3 Calculate the combination load for the reinforcement concrete beam shown in Figure 3. Unit: KN/m with two decimal. 1.2G+1.5Q=w
The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f'c = 25MPa 800 730 N12 ligs (fx.t-500MPa) Ast = 3N28 350 Span = 10m Figure 3 Use the Transformed section approach considering the presence of steel. Calculate the concrete area and transformed steel area in both tension and compression shown in Figure 3. n=Es/Ec Ast=1232mm^2 Use n-1 for the transformed area to do the calculate. Unit: mm^2 with two decimal
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*4-36. The composite bar consists of a 20-mm-diameter A-36 steel segment AB and 50-mm-diameter red brass C83400 end segments DA and CB. Determine the average normal stress in each segment due to the applied load. Esteel l = 200 x10 Pa. EBrass = 101 K109h. |-250 mm-- 500 mm -250 mm- 50 mm 20 mm 75 kN 100 kN D A 75 kN 100 kN В C
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c) Find the stresses in the concrete and the reinforcement for the following applied moments: (i) – M1= 35kN.m and (ii) – 120kN.m Cross-section: width height Modulus of elasticity: concrete reinforcement Reinforcement: depth area b:= 300-mm h := 520-mm Ec:= 30-GPa Es:= 200-GPa d:= 460-mm As 1470-mm 2 h d b
REINFORCED CONCRTE DESIGN
Problem 1. The composite beam shown below carries a cantilevered load of 10 kN. The beam consists of one 30 x 124 mm plate and four 12 x 50 mm plates. They are pinned together at 120 mm intervals with round pins. The pin material has a shear strength of 159 MPa. Compute the minimum acceptable diameter for the pins. O O O O O O O -0 O 0- O 1000 mm Do O -120 mm (typ) O O O P = 10 KN 30 x 124 mm 12 x 50 mm (typ)
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The T-beam shown in figure resulted from monolithic construction of the beam and slab. The effective flange width is 1100 mm and the uniform slab thickness is 120mm. Width of beam is 340 mm, total depth of the T-section is 590 mm. The centroid of steel is 70 mm from extreme concrete fiber. Concrete strength f’c= 21 MPa amd steel strength fy= 415 MPa. 1 Calculate the nominal strength of the beam for positive moment neglecting the contribution of the top reinforcement, KN-m A 428.55 B 503.20 C 355.96 D 637.52 2 Calculate the nominal strength of the beam for negative moment, KN-m A 289.88 B 275.53 C 311.67 D 325.48
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