3. A 24 ft long, simply supported beam carries only a uniform live load (WL). The beam has the following properties: fy= 60 ksi f.= 3,000 psi • b = 14 in • d = 26 in • h = 30 in • Steel: contains five (5) # 8 bars. Compute the depth of the compressive stress block (a) and the actual percentage of reinforcement (p). b) Compute the R value and use this to compute the moment capacity (M) in kip ft. c) Use the M; value to solve for the ultimate moment (M.). The use this value to solve for the uniform live load (WL) in units of k/ft without the live load service factor (1.6).

3. A 24 ft long, simply supported beam carries only a uniform live load (WL). The beam has the following properties: fy= 60 ksi f.= 3,000 psi • b = 14 in • d = 26 in • h = 30 in • Steel: contains five (5) # 8 bars. Compute the depth of the compressive stress block (a) and the actual percentage of reinforcement (p). b) Compute the R value and use this to compute the moment capacity (M) in kip ft. c) Use the M; value to solve for the ultimate moment (M.). The use this value to solve for the uniform live load (WL) in units of k/ft without the live load service factor (1.6).

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

3. A 24 ft long, simply supported beam carries only a uniform live load (W). The beam has the
following properties:
f,= 60 ksi
f= 3,000 psi
• b = 14 in
d = 26 in
• h = 30 in
Steel: contains five (5) # 8 bars.
a)
Compute the depth of the compressive stress block (a) and the actual percentage of
reinforcement (p).
b)
Compute the R value and use this to compute the moment capacity (M.) in kip ft.
c)
Use the M; value to solve for the ultimate moment (M.). The use this value to solve for the
uniform live load (WL) in units of k/ft without the live load service factor (1.6).

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