Preparing a standard curve. 1. determine the absorbance max of [FeSCN]2+               it is 448.1 2. determine the concentration of FeSCN2+ in the stock solution.            M1V1=M2V2   stock solution: ~0.200 M iron (iii) nitrate in 1M nitric acid intial volume: 0.3mL final volume: 10.3mL volume: 10mL   ~0.002M potassium thiocyanate initial volume: 0.3mL final volume: 10.3mL volume: 10mL     not sure if this is needed stock solutions: ~0.200M iron (iii) nitrate in 1M nitric acid: 0.207M ~0.002M iron (iii) nitrate in 1M nitric acid: 0.00209M ~0.002M potassium thiocyanate: 0.00193M

Q: 8.00 mL of 6.00 x 10-3 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to…

A: We have to calculate the initial moles of SCN-.

Q: 6.00 mL of 8.00 x 10-3 M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: Given that : Volume of Fe(NO3)3 = 6.00 mL Concentration of Fe(NO3)3 = 8.00 x 10-3 M Volume of KSCN =…

Q: 5.00 mL of 7.00 x 10¯³ M Fe(NO3)3 (7.00 times 10 to the minus 3rd power MFe (NO3)3) is added to 7.00…

A: Molarity of Fe3+  ions = 7.00 × 10-3 M Total Volume = 5 + 7 + 5 = 17 ml = 0.017 L

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A:

Q: Find the solubility of Cr(OH)₃ in a buffer of pH 13.0 [Kₛₚ of Cr(OH)₃ =6.3X10⁻³¹; Kբ of…

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Q: Standard solution of Copper (I) complex (111 g/mole) with a concentration of 1.0 mg /mL had an…

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Q: 7.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 6.00…

A: Initial Molarity of Fe3+ solution = 5.00×10-3mol/L Initial Volume of Fe3+ solution = 7.00 mL…

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A: EDTA forms complex with ions in 1 : 1 mole ratio. So first we would write the reactions.  Then we…

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A: We have find out the answer.

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Q: A 0.3674 g powdered milk sample was analyzed for calcium by igniting in a crucible at 1000°C, the…

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Q: 4.00 mL of 4.00 x 103 M. Fe(NO3)3 (4.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to…

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Q: 7.00 mL of 5.00 x 10-3 M. Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to…

A: We have to calculate the moles of Fe+3 at equilibrium.

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Q: 9.00 mL of 9.00 x 10-³ M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: We will first calculate the millimoles of all the reactants added and the millimoles of the final…

Q: 6.00 mL of 5.00 × 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: Mole is the amount of the substance that contains the same number of particles or atoms or…

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A:

Q: We can determine the copper(II) ion content of a sample using spectrophotometry. The following data…

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Q: 8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A:

Q: The total concentration of Ca²+ and Mg²+ in a sample of hard water was determined by titrating a…

A: SOLUTION: Step 1: The concentration of magnesium ion is calculated as follows:

Q: 8.00 mL of 6.00 x 10-3 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to…

A: Given that : Given that :Initial volume of Fe(NO3)3 = 8.00 mLMolarity of  Fe(NO3)3 =…

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A:

Q: 5.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 7.00…

A: Given: Concentration of Fe(NO3)3 taken = 5.00 × 10-3 M Volume of Fe(NO3)3 solution taken = 5.00 mL…

Q: PHASE 10: A Lab Data - X Calculate Equilibrium Constant Prepared solutions, absorbance, and…

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Q: 9.00 mL of 7.00 x 10 M Fe(NO3)3 (7.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 4.00…

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Q: If, at equilibrium, the solution prepared in Problem #1 has an absorbance of 0.36, what is the…

A: The absorbance of a solution directly related to the type of solute and concentration of solute.

Q: 7.00 mL of 8.00 x 103 M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 6.00…

A: Total concentration of [Fe(SCN)2+] at equilibrium = 1.00×10-4 Thus the concentration of Fe3+ at…

Q: 7.00 mL of 5.00 x 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A:

Q: 8.00 mL of 5.00 x 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: Given that : Volume of Fe(NO3)3 = 8.00 mL Concentration of KSCN = 5.00 x 10-3 M Volume of KSCN =…

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Q: 8.00 mL of 9.00 x 10-3 M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: Volume of Fe(NO3)3 = 8ml Concentratio of Fe(NO3)3 = 9×10-3M Volume of KSCN = 5ml Concentratio of…