7.00 mL of 8.00 x 10³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M Fe(NO3)3) is added to 6.00 mL of 4.00 x 103 M KSCN (4.00 times 10 to the minus 3rdpower M KSCN) along with 3.00 mL of water. The concentration of [F e(SCN)2] wasfound to be 1.00 x 104 M (1.00 times 10 to the minus 4th power M) atequilibrium.How many moles of Fe+ are present in the solution at equilibrium?Express your answer as a decimal number (no exponents).

Total concentration of [Fe(SCN)2+] at equilibrium = 1.00×10-4 Thus the concentration of Fe3+ at…

7.00 mL of 8.00 x 103 M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 6.00 mL of 4.00 x 103 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 3.00 mL of water. The concentration of [F e(SCN)21 was found to be 1.00 x 104 M (1.00 times 10 to the minus 4th power M) at equilibrium.How many moles of Fe3+ are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

7.00 mL of 8.00 x 103 M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 6.00 mL of 4.00 x 103 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 3.00 mL of water. The concentration of [F e(SCN)21 was found to be 1.00 x 104 M (1.00 times 10 to the minus 4th power M) at equilibrium.How many moles of Fe3+ are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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