4.00 mL of 4.00 x 103 M. Fe(NO3)3 (4.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 9.00 mL of 6.00 x 103 M KSCN (6.00 times 10 to the minus 3rd power M KSCN) along with 3.00 mL of water. The concentration of [F e(SCN)2*] was found to be 1.00 x 104 M (1.00 times 10 to the minus 4th power M) at equilibrium.How many moles of [F e(SCN)2*] are present in the solution? Express your answer as a decimal number (no exponents). Your Answer:

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4.00 mL of 4.00 x 103 M
Fe(NO3)3 (4.00 times 10 to the minus
3rd power MFe (NO3)3) is added to
9.00 mL of 6.00 x 103 M KSCN
(6.00 times 10 to the minus 3rd power
M KSCN) along with 3.00 mL of water.
The concentration of [F e(SCN)2+] was
found to be 1.00 x 10-4 M (1.00 times
10 to the minus 4th power M) at
equilibrium.How many moles of [F
e(SCN)2+] are present in the solution?
Express your answer as a decimal
number (no exponents).
Your Answer:
Answer
units
Transcribed Image Text:4.00 mL of 4.00 x 103 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power MFe (NO3)3) is added to 9.00 mL of 6.00 x 103 M KSCN (6.00 times 10 to the minus 3rd power M KSCN) along with 3.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-4 M (1.00 times 10 to the minus 4th power M) at equilibrium.How many moles of [F e(SCN)2+] are present in the solution? Express your answer as a decimal number (no exponents). Your Answer: Answer units
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