9.00 mL of 6.00 x 10-3 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 5.00 mL of 6.00 x 10-3 M KSCN (6.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-4 M (1.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN¯ (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents). X Your Answer: Answer units
9.00 mL of 6.00 x 10-3 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 5.00 mL of 6.00 x 10-3 M KSCN (6.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-4 M (1.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN¯ (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents). X Your Answer: Answer units
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![9.00 mL of 6.00 x 103 M
Fe(NO3)3 (6.00 times 10 to the minus 3rd
power M Fe (NO3)3) is added to 5.00 mL
of 6.00 x 10-3 M KSCN (6.00 times 10 to
the minus 3rd power M KSCN) along with
4.00 mL of water. The concentration of [F
e(SCN)2*] was found to be 1.00 x 10-4 M
(1.00 times 10 to the minus 4th power M)
at equilibrium. How many moles of
SCN" (SCN minus) are present in the
solution at equilibrium? Express your
answer as a decimal number (no
exponents).
Your Answer:
Answer
units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c763d77-630d-4469-a365-be95d47bd936%2Fee878ca1-1dc6-4c55-b696-295a585519a7%2F0z032j9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9.00 mL of 6.00 x 103 M
Fe(NO3)3 (6.00 times 10 to the minus 3rd
power M Fe (NO3)3) is added to 5.00 mL
of 6.00 x 10-3 M KSCN (6.00 times 10 to
the minus 3rd power M KSCN) along with
4.00 mL of water. The concentration of [F
e(SCN)2*] was found to be 1.00 x 10-4 M
(1.00 times 10 to the minus 4th power M)
at equilibrium. How many moles of
SCN" (SCN minus) are present in the
solution at equilibrium? Express your
answer as a decimal number (no
exponents).
Your Answer:
Answer
units
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