Calculate the equilibrium concentrations of Fe3+, Fe2+, Mn2+, MnO4 in a solution prepared by mixing 20.0 mL of 0.100 M KMnO4 and 20.0 mL of 0.100 M FeSO4 at pH 0.00. EMnO/Mn²+ = 1.51 V, Efe/Fe²+ = 0.771 V MnO +5Fe2+ + 8H+ - ->> Mn²+ + 5Fe³+ + 4H₂O
Calculate the equilibrium concentrations of Fe3+, Fe2+, Mn2+, MnO4 in a solution prepared by mixing 20.0 mL of 0.100 M KMnO4 and 20.0 mL of 0.100 M FeSO4 at pH 0.00. EMnO/Mn²+ = 1.51 V, Efe/Fe²+ = 0.771 V MnO +5Fe2+ + 8H+ - ->> Mn²+ + 5Fe³+ + 4H₂O
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section12.3: Determining Equilibrium Constants
Problem 12.3PSP
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![Calculate the equilibrium concentrations of Fe3+, Fe2+, Mn2+, MnO4 in a
solution prepared by mixing 20.0 mL of 0.100 M KMnO4 and 20.0 mL of
0.100 M FeSO4 at pH 0.00. EMnO/Mn²+ = 1.51 V, Efe+/Fe²+ = 0.771 V
MnO + 5Fe2+ + 8H+ -
Mn²+ + 5Fe³++ 4H₂O
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F80288942-0161-4408-ab65-d51fe2329570%2Fd10ee10b-6f25-4793-9c49-a9ea6eb7fdc5%2Fxhsq3p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the equilibrium concentrations of Fe3+, Fe2+, Mn2+, MnO4 in a
solution prepared by mixing 20.0 mL of 0.100 M KMnO4 and 20.0 mL of
0.100 M FeSO4 at pH 0.00. EMnO/Mn²+ = 1.51 V, Efe+/Fe²+ = 0.771 V
MnO + 5Fe2+ + 8H+ -
Mn²+ + 5Fe³++ 4H₂O
4
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