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Calculate the equilibrium concentrations of Fe3+, Fe2+, Mn2+, MnO4– in a solution prepared by mixing 20.0 mL of 0.100 M KMnO4 and 20.0 mL of 0.100 M FeSO4 at pH 0.00.   E°MnO4- /Mn 2+ = 1.51 V   E°Fe3+ /Fe2+ = 0.771 V     MnO4- + 5Fe 2+ + 8H + ⟶ Mn2+ + 5Fe 3+ + 4H2 O Answer: [MnO4–] = 0.0400 M; [Mn2+] = 0.0100 M; [Fe3+] = 0.0500 M; [Fe2+] = 1.1 × 10–14 M

Calculate the equilibrium concentrations of Fe3+, Fe2+, Mn2+, MnO4– in a solution prepared by mixing 20.0 mL of 0.100 M KMnO4 and 20.0 mL of 0.100 M FeSO4 at pH 0.00.   E°MnO4- /Mn 2+ = 1.51 V   E°Fe3+ /Fe2+ = 0.771 V     MnO4- + 5Fe 2+ + 8H + ⟶ Mn2+ + 5Fe 3+ + 4H2 O Answer: [MnO4–] = 0.0400 M; [Mn2+] = 0.0100 M; [Fe3+] = 0.0500 M; [Fe2+] = 1.1 × 10–14 M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Calculate the equilibrium concentrations of Fe3+, Fe2+, Mn2+, MnO4– in a

solution prepared by mixing 20.0 mL of 0.100 M KMnO4 and 20.0 mL of

0.100 M FeSO4 at pH 0.00.

 

E°MnO4- /Mn 2+ = 1.51 V

 

E°Fe3+ /Fe2+ = 0.771 V

 

 

MnO4- + 5Fe 2+ + 8H + ⟶ Mn2+ + 5Fe 3+ + 4H2 O

Answer:

[MnO4–] = 0.0400 M; [Mn2+] = 0.0100 M; [Fe3+] = 0.0500 M;

[Fe2+] = 1.1 × 10–14 M

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