The Ka expression for the H, PO,/HPO;- buffer is given Ionic strength (µ, M) 0.005 0.010 0.050 0.10 by the equation YH+ 0.933 0.914 0.86 0.83 0.740 0.660| 0.445 0.355 [HPO;] YHPO;- [H*] YH• K, = YHPO - = 10-7.20 [H, PO] YH,PO; YH, PO, 0.928 0.902 0.82 |0.775 What is the pH of a 1:1 mixture of H, PO, to HPO;- at an ionic strength of 0.005 M? Activity coefficients can be found in the table. pH = 6.77

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Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 33QAP: A buffer is prepared in which the ratio [ H2PO4 ]/[ HPO42 ]is 3.0. (a) What is the pH of this...
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The Ka expression for the H, PO,/HPO?- buffer is given
Ionic strength (µ, M)
0.005 0.010 0.050 | 0.10
by the equation
YH+
0.933 0.914 0.86
0.83
[HPO] YHPO;- [H*] YH*
Ka =
[H,PO;] YH,PO;
YHPO; -
0.740 0.660 0.445 0.355
10-7.20
YH,PO,
0.928 0.902 0.82 0.775
What is the pH of a 1:1 mixture of H, PO, to HPO?- at
an ionic strength of 0.005 M? Activity coefficients can be
found in the table.
pH
6.77
Transcribed Image Text:The Ka expression for the H, PO,/HPO?- buffer is given Ionic strength (µ, M) 0.005 0.010 0.050 | 0.10 by the equation YH+ 0.933 0.914 0.86 0.83 [HPO] YHPO;- [H*] YH* Ka = [H,PO;] YH,PO; YHPO; - 0.740 0.660 0.445 0.355 10-7.20 YH,PO, 0.928 0.902 0.82 0.775 What is the pH of a 1:1 mixture of H, PO, to HPO?- at an ionic strength of 0.005 M? Activity coefficients can be found in the table. pH 6.77
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