8.00 mL of 6.00 x 10-3 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 6.00 mL of 5.00 x 103 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 3.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 1o-4 M (1.00 times 10 to the minus 4th power M) at equilibrium.How many moles of [F e(SCN)2+] are present in the solution? Express your answer as a decimal number (no exponents).
8.00 mL of 6.00 x 10-3 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 6.00 mL of 5.00 x 103 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 3.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 1o-4 M (1.00 times 10 to the minus 4th power M) at equilibrium.How many moles of [F e(SCN)2+] are present in the solution? Express your answer as a decimal number (no exponents).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Given,
Volume of Fe(NO3)3 = 8.00 mL
Molarity of Fe(NO3)3 = 6.00 x 10-3 M
Volume of KSCN = 6.00 mL
Molarity of KSCN = 5.00 x 10-3 M
Volume of water = 3.00 mL
Molarity of [Fe(SCN)2+] at equilibrium stage = 1.00 x 10-4 M
Number of moles of [Fe(SCN)2+] in the solution = ?
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