5.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 7.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2*] was found to be 2.00 x 104 M (2.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN¯ (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
5.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 7.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2*] was found to be 2.00 x 104 M (2.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN¯ (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Question
![5.00 mL of 5.00 x 103 M
Fe(NO3)3 (5.00 times 10 to the minus
3rd power MF (NO3)3) is added to
7.00 mL of 5.00 x 103 M KSCN
(5.00 times 10 to the minus 3rd power
M KSCN) along with 5.00 mL of water.
The concentration of [F e(SCN)2+] was
found to be 2.00 x 104 M (2.00 times
10 to the minus 4th power M) at
equilibrium. How many moles of
SCN (SCN minus) are present in the
solution at equilibrium? Express your
answer as a decimal number (no
exponents).
Your Answer:
Answer
units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f7858f2-4558-4a97-afcd-256e507c1a66%2F6e33eb05-ca5e-4db4-a1be-0d85eed8ec2e%2Fawi1e5l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5.00 mL of 5.00 x 103 M
Fe(NO3)3 (5.00 times 10 to the minus
3rd power MF (NO3)3) is added to
7.00 mL of 5.00 x 103 M KSCN
(5.00 times 10 to the minus 3rd power
M KSCN) along with 5.00 mL of water.
The concentration of [F e(SCN)2+] was
found to be 2.00 x 104 M (2.00 times
10 to the minus 4th power M) at
equilibrium. How many moles of
SCN (SCN minus) are present in the
solution at equilibrium? Express your
answer as a decimal number (no
exponents).
Your Answer:
Answer
units
Expert Solution

Step 1
Given: Concentration of Fe(NO3)3 taken = 5.00 × 10-3 M
Volume of Fe(NO3)3 solution taken = 5.00 mL
Concentration of KSCN taken = 5.00 × 10-3 M
Volume of KSCN solution taken = 7.00 mL.
The volume of water added = 5.00 mL.
And the equilibrium concentration of Fe(SCN)2+ = 2.00 × 10-4 M
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