Paraxial design of a field flattener. Imagine your optical system has Petzal curvature of the field with radiusp. In Module 1 of Course 1, a homework problem asked you to derive the paraxial focus shift along the axiswhen a slab of glass was inserted in a converging cone of rays. Find or re-derive that result, then use it tocalculate the paraxial radius of curvature of a field flattener of refractive index n that will correct the observedPetzval. Assume that the side of the flattener facing the image plane is plano. What is the required radius ofthe plano-convex field flattener? (p written as rho )

Step 1:Recall or re-derive the paraxial focus shift:The paraxial focus shift, Δz, when a slab of…

Answered: Paraxial design of a field flattener.…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter38: Refraction And Images Formed By Refraction

Section: Chapter Questions

Problem 126PQ

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You can argue that a that piece of glass, such as in a window, is like a lens with an infinite focal length. If so, where does it form an image? That is, how are diand dorelated?
By ray tracing or by calculation, find the place inside the glass where rays from S converge as a result of refraction through the lens and the convex air-glass interface. Use a ruler to estimate the radius of curvature.
A 7.5 binocular produces an angular magnification of —7.50, acting like a telescope. (Mirrors are used to make the image upright.) If the binoculars have objective lenses with a 75.0-cm focal length, what is the focal length of the eyepiece lenses?
A point source of light is 50 cm in front of a converging lens of focal length 30 cm. A concave mirror with a focal length of 20 cm is placed 25 cm behind the lens. Where does the final image form, and what are its orientation and magnification?
Figure P38.43 shows a concave meniscus lens. If |r1| = 8.50 cm and |r2| = 6.50 cm, find the focal length and determine whether the lens is converging or diverging. The lens is made of glass with index of refraction n = 1.55. CHECK and THINK: How do your answers change if the object is placed on the right side of the lens? FIGURE P38.43
(a) Using information in the preceding problem, find the height of the instructor’s head above the water, noting that you will first have to calculate the angle of incidence. (b) Find the apparent depth of the diver’s head below water as seen by the instructor.
The left face of a biconvex lens has a radius of curvature of magnitude 12.0 cm, and the right face has a radius of curvature of magnitude 18.0 cm. The index of refraction of the glass is 1.44. (a) Calculate the focal length of the lens for light incident from the left. (b) What If? After the lens is turned around to interchange the radii of curvature of the two faces, calculate the focal length of the lens for light incident from the left.
You can determine the index of refraction of a substance by determining its critical angle. (a) What is the index of refraction of a substance that has a critical angle of 68.4° when submerged in water? What Is the substance, based on Table 1.1? (b) What would the critical angle be for this substance in air?
An object is located in water 30 cm from the vertex of a convex surface made of Plexiglas with a radius of curvature of 80 cm. Where does the image form by refraction and what is its magnification? nwater=4/3 and nPlexiglas=1.65.
(a) Using information in Figure 25.53, find the height of the instructor's head above the water, noting that you will first have to calculate the angle of incidence. (b) Find the apparent depth of the diver’s head below water as seen by the instructor.
Find the focal length of a meniscus lens with R1=20cmand R2=15cm . Assume that the index of refraction of the lens is 1.5.
The far point of a myopic administrator is 50.0 cm. (a) What is the relaxed power of his eyes? (b) If he has the normal 8.00% ability to accommodate, what is the closest object lie can see clearly?

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