If a toy car is on a circular hot-wheels track with a radius of 25.0 cm, and the speed of the car is 1.60 m/s. What is the centripetal acceleration of the car? And if the car has a mass of 18 grams, what is the net force required to keep the car on the track? If the same toy car were now traveling through a vertical loop with a radius of 25.0 cm. What would be the minimum speed at the top of the loop required to keep the car from falling out of the loop?

A roller-coaster track is set with hills and valleys as shown in the figure. A roller-coaster car crests hill "A" at 5 m/s. What force will provide the centripetal force needed for the car to stay on this circular path? 200 OA Weight OB Tension OC. Normal force Op Friction C 160 m

From the figure provided, which has/have the second largest centripetal acceleration? Select all that apply. Select all that are true.a c d e b

Modern roller coasters have vertical loops like the one shown in the figure. The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. What is the speed of the roller coaster, in meters per second, at the top of the loop if the radius of curvature there is 11 m and the downward acceleration of the car is 1.2g? Note that g here is the acceleration due to gravity.  The beginning of this roller coaster is at the top of a high hill. If it started from rest at the top of this hill, how high, in meters, above the top of the loop is this initial starting point? You may assume there is no friction anywhere on the track.  If it actually starts 4.5 m higher than your answer to the previous part (yet still reaches the top of the loop with the same velocity), how much energy, in joules, did it lose to friction? Its mass is 1500…

Modern roller coasters have vertical loops like the one shown. The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. What is the speed of the roller coaster at the top of the loop if the radius of curvature there is 15.0 m and the downward acceleration of the car is 1.50 g?

Modern roller coasters have vertical loops like the one shown here. The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. (a) What is the speed of the roller coaster at the top of the loop if the radius of curvature there is 15.0 m and the downward acceleration of the car is 1.50 g? (b) How high above the top of the loop must the roller coaster start from rest, assuming negligible friction? (c) If it actually starts 5.00 m higher than your answer to (b), how much energy did it lose to friction? Its mass is 1.50 × 103 kg .

A car is driving on circular test track of radius 900 m at a constant tranlational speed. The friction foce between the tire and the track provides the centripetal force to keep the car in the corcular motion. If the lap time of the car is 58 s and the mass of the car is 1200 kg. fond the magnitude of the frictional force between the tire and the track in the unit N.

it takes a 600kg racing car 10 secs to travel at a uniform speed around a circular track with a radius of 50m. What average force must the car's tires exert against the track tp maintain this circular motion? What is the acceleration of the car?

A centripetal force of 36.1N is exerted in a 2.5kg sphere causing it to rotate uniformly on a horizontal circle with radius of 1.5m. Ignore air resistance and gravity. What is the speed of the sphere in m/s

A 14000N car traveling at 25m/s rounds a curve of radius 200m.Find the following: A) The centripetal acceleration of the car.  B) The force that maintain centripetal acceleration. C) The minimum coefficient of statistic  friction between the tires and road that will allow the car to round the curve safely.