Molecule: PF3 indicate the number of available electrons that are ae = in the molecule. in the space to the right connect all of the atoms Trial Structure to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? ne = Circle the correct ne = ae ne < ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geOm Hybridization:
Molecule: PF3 indicate the number of available electrons that are ae = in the molecule. in the space to the right connect all of the atoms Trial Structure to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? ne = Circle the correct ne = ae ne < ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geOm Hybridization:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![2. Molecule: PF3
indicate the number of
available electrons that are
ae =
in the molecule.
in the space to the right
connect all of the atoms
to the central atom and
then make each atom
Trial Structure:
follow the octet rule (duet
rule for hydrogen).
How
many
electrons are
necessary in the trial
structure?
ne =
Circle the correct
ne = ae
ne < ae
ne>ae
relationship between ne
and ae.
Draw the corrected Lewis
Structure to the right.
Add Later:
e- geometry:
molecular gEOm
Hybridization:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a6f2e6d-caf3-4f31-a0f0-c8e5156c1788%2Ff5c27c4b-c4b9-4b87-b457-789f4c6d2ceb%2Fyebwdo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Molecule: PF3
indicate the number of
available electrons that are
ae =
in the molecule.
in the space to the right
connect all of the atoms
to the central atom and
then make each atom
Trial Structure:
follow the octet rule (duet
rule for hydrogen).
How
many
electrons are
necessary in the trial
structure?
ne =
Circle the correct
ne = ae
ne < ae
ne>ae
relationship between ne
and ae.
Draw the corrected Lewis
Structure to the right.
Add Later:
e- geometry:
molecular gEOm
Hybridization:
![2. Molecule: PF3
indicate the number of
available electrons that are
ae =
in the molecule.
in the space to the right
connect all of the atoms
to the central atom and
then make each atom
Trial Structure:
follow the octet rule (duet
rule for hydrogen).
How
many
electrons are
necessary in the trial
structure?
ne =
Circle the correct
ne = ae
ne < ae
ne>ae
relationship between ne
and ae.
Draw the corrected Lewis
Structure to the right.
Add Later:
e- geometry:
molecular gEOm
Hybridization:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a6f2e6d-caf3-4f31-a0f0-c8e5156c1788%2Ff5c27c4b-c4b9-4b87-b457-789f4c6d2ceb%2Fik07iw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Molecule: PF3
indicate the number of
available electrons that are
ae =
in the molecule.
in the space to the right
connect all of the atoms
to the central atom and
then make each atom
Trial Structure:
follow the octet rule (duet
rule for hydrogen).
How
many
electrons are
necessary in the trial
structure?
ne =
Circle the correct
ne = ae
ne < ae
ne>ae
relationship between ne
and ae.
Draw the corrected Lewis
Structure to the right.
Add Later:
e- geometry:
molecular gEOm
Hybridization:
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