1. Molecule: CF4 indicate the number of Jelectrons available electrons that are in the molecule. in the space to the right connect all of the atoms to the central atom and then make each atom follow the octet rule ae = Trial Structure: (duet rule for hydrogen). How many electrons are necessary in the trial structure? he = Circle the correct ne = ae ne < ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular gesom Hybridization:

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**1. Molecule: CF₄**

**Instructions:**

- Indicate the number of available electrons in the molecule.

  \( ae = \_\_\_\_ \text{ electrons} \_\_\_\_\_ \)

**Trial Structure:**

- In the space to the right, connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen).

---

**Questions:**

1. How many electrons are necessary in the trial structure?

   \( ne = \_\_\_\_\_ \)

2. Circle the correct relationship between \(ne\) and \(ae\).

   \( ne = ae \) \hspace{15pt} \( ne < ae \) \hspace{15pt} \( ne > ae \)

3. Draw the corrected Lewis Structure to the right.

**Add Later:**

- \( e\text{- geometry}: \_\_\_\_\_\_\_\_\_ \)

- molecular \( geom: \_\_\_\_\_\_\_\_ \)

- Hybridization: \_\_\_\_\_\_\_

Note: This worksheet is used to determine the electron count and structures for the CF₄ molecule, helping understand molecular geometry and hybridization concepts.
Transcribed Image Text:**1. Molecule: CF₄** **Instructions:** - Indicate the number of available electrons in the molecule. \( ae = \_\_\_\_ \text{ electrons} \_\_\_\_\_ \) **Trial Structure:** - In the space to the right, connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). --- **Questions:** 1. How many electrons are necessary in the trial structure? \( ne = \_\_\_\_\_ \) 2. Circle the correct relationship between \(ne\) and \(ae\). \( ne = ae \) \hspace{15pt} \( ne < ae \) \hspace{15pt} \( ne > ae \) 3. Draw the corrected Lewis Structure to the right. **Add Later:** - \( e\text{- geometry}: \_\_\_\_\_\_\_\_\_ \) - molecular \( geom: \_\_\_\_\_\_\_\_ \) - Hybridization: \_\_\_\_\_\_\_ Note: This worksheet is used to determine the electron count and structures for the CF₄ molecule, helping understand molecular geometry and hybridization concepts.
**1. Molecule: CF₄**

- **Indicate the number of available electrons that are in the molecule.**

  - \( ae = \_\_\_\_ \) electrons

- **Trial Structure:**

  - In the space to the right, connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen).

---

- **How many electrons are necessary in the trial structure?**

  - \( ne = \_\_\_\_ \)

- **Circle the correct relationship between \( ne \) and \( ae \).**

  - \( ne = ae \)

  - \( ne < ae \)

  - \( ne > ae \)

- **Draw the corrected Lewis Structure to the right.**

- **Add Later:**

  - \( e\text{-geometry} : \_\_\_\_ \)

  - \( \text{molecular geom.} : \_\_\_\_ \)

  - \( \text{Hybridization:} \_\_\_\_ \)
Transcribed Image Text:**1. Molecule: CF₄** - **Indicate the number of available electrons that are in the molecule.** - \( ae = \_\_\_\_ \) electrons - **Trial Structure:** - In the space to the right, connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). --- - **How many electrons are necessary in the trial structure?** - \( ne = \_\_\_\_ \) - **Circle the correct relationship between \( ne \) and \( ae \).** - \( ne = ae \) - \( ne < ae \) - \( ne > ae \) - **Draw the corrected Lewis Structure to the right.** - **Add Later:** - \( e\text{-geometry} : \_\_\_\_ \) - \( \text{molecular geom.} : \_\_\_\_ \) - \( \text{Hybridization:} \_\_\_\_ \)
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