III the space to the right Trial Structure: connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? Circle the correct ne = ne = ae ne < ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geom: Hybridization:

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### SF₆ Molecule Structure Analysis

---

**9. Molecule: SF₆**

- **Available Electrons:**
  - Indicate the number of available electrons in the molecule.
  - **ae =** ______

- **Trial Structure:**
  - In the space to the right, connect all atoms to the central atom, ensuring each atom follows the octet rule (except for hydrogen, which follows the duet rule).

- **Electrons Necessary:**
  - How many electrons are required in the trial structure?
  - **ne =** ______

- **Comparative Analysis:**
  - Circle the correct relationship between necessary electrons (ne) and available electrons (ae):
    - ne = ae
    - ne < ae
    - ne > ae

- **Lewis Structure:**
  - Draw the corrected Lewis structure to the right.

- **Additional Details (Add Later):**
  - **Electron Geometry:** ______
  - **Molecular Geometry:** ______
  - **Hybridization:** ______

---

This worksheet guides students through the process of determining the electron arrangement and molecular geometry of sulfur hexafluoride (SF₆). It involves calculating available and necessary electrons, drawing Lewis structures, and understanding molecular geometry and hybridization concepts.
Transcribed Image Text:### SF₆ Molecule Structure Analysis --- **9. Molecule: SF₆** - **Available Electrons:** - Indicate the number of available electrons in the molecule. - **ae =** ______ - **Trial Structure:** - In the space to the right, connect all atoms to the central atom, ensuring each atom follows the octet rule (except for hydrogen, which follows the duet rule). - **Electrons Necessary:** - How many electrons are required in the trial structure? - **ne =** ______ - **Comparative Analysis:** - Circle the correct relationship between necessary electrons (ne) and available electrons (ae): - ne = ae - ne < ae - ne > ae - **Lewis Structure:** - Draw the corrected Lewis structure to the right. - **Additional Details (Add Later):** - **Electron Geometry:** ______ - **Molecular Geometry:** ______ - **Hybridization:** ______ --- This worksheet guides students through the process of determining the electron arrangement and molecular geometry of sulfur hexafluoride (SF₆). It involves calculating available and necessary electrons, drawing Lewis structures, and understanding molecular geometry and hybridization concepts.
## Transcription for Educational Website

### Molecule: SF₆

1. **Available Electrons in the Molecule**  
   - Indicate the number of available electrons that are in the molecule.  
   - **ae** = _____________

2. **Trial Structure**  
   - In the space provided, connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen).

3. **Necessary Electrons in the Trial Structure**
   - How many electrons are necessary in the trial structure?  
   - **ne** = _____________

4. **Relationship Between Electrons**
   - Circle the correct relationship between ne and ae:  
     - ne = ae  
     - ne < ae  
     - ne > ae  

5. **Drawing the Lewis Structure**
   - Draw the corrected Lewis Structure to the right.

6. **Additional Information to Add Later:**
   - **Electron Geometry:** ________________
   - **Molecular Geometry:** ________________
   - **Hybridization:** ________________
Transcribed Image Text:## Transcription for Educational Website ### Molecule: SF₆ 1. **Available Electrons in the Molecule** - Indicate the number of available electrons that are in the molecule. - **ae** = _____________ 2. **Trial Structure** - In the space provided, connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). 3. **Necessary Electrons in the Trial Structure** - How many electrons are necessary in the trial structure? - **ne** = _____________ 4. **Relationship Between Electrons** - Circle the correct relationship between ne and ae: - ne = ae - ne < ae - ne > ae 5. **Drawing the Lewis Structure** - Draw the corrected Lewis Structure to the right. 6. **Additional Information to Add Later:** - **Electron Geometry:** ________________ - **Molecular Geometry:** ________________ - **Hybridization:** ________________
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