7. Molecule: NO3 indicate the number of available electrons that are ae = in the molecule. in the space to the right connect all of the atoms Trial Structure: to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? he = Circle the correct ne < ae ne = ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geom: Hybridization:

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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7. Molecule: NO3
indicate the number of
available electrons that are
ae =
in the molecule.
in the space to the right
connect all of the atoms
Trial Structure:
to the central atom and
then make each atom
follow the octet rule (duet
rule for hydrogen).
How many electrons are
necessary in the trial
structure?
ne =
Circle the correct
ne = ae
ne < ae
ne>ae
relationship between ne
and ae.
Draw the corrected Lewis
Structure to the right.
Add Later:
e- geometry:
molecular geom:
Hybridization:
Transcribed Image Text:7. Molecule: NO3 indicate the number of available electrons that are ae = in the molecule. in the space to the right connect all of the atoms Trial Structure: to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? ne = Circle the correct ne = ae ne < ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geom: Hybridization:
7. Molecule: NO3
indicate the number of
available electrons that are
ae =
in the molecule.
in the space to the right
connect all of the atoms
Trial Structure:
to the central atom and
then make each atom
follow the octet rule (duet
rule for hydrogen).
How many electrons are
necessary in the trial
structure?
ne =
Circle the correct
ne = ae
ne < ae
ne>ae
relationship between ne
and ae.
Draw the corrected Lewis
Structure to the right.
Add Later:
e- geometry:
molecular geom:
Hybridization:
Transcribed Image Text:7. Molecule: NO3 indicate the number of available electrons that are ae = in the molecule. in the space to the right connect all of the atoms Trial Structure: to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? ne = Circle the correct ne = ae ne < ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geom: Hybridization:
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