3. Molecule: C¿H4 indicate the number of available electrons that are in the molecule. in the space to the right connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). ae = Trial Structure:

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3. Molecule: CH4
indicate the number of
available electrons that are
in the molecule.
ae =
Trial Structure:
in the space to the right
connect all of the atoms
to the central atom and
then make each atom
follow the octet rule (duet
rule for hydrogen).
How many electrons are
necessary in the trial
structure?
Circle the correct
ne =
ne = ae
ne < ae
ne>ae
relationship between ne
and ae.
Draw the corrected Lewis
Structure to the right.
Add Later:
e- geometry:
molecular geom
Hybridization:
Transcribed Image Text:3. Molecule: CH4 indicate the number of available electrons that are in the molecule. ae = Trial Structure: in the space to the right connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? Circle the correct ne = ne = ae ne < ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geom Hybridization:
3. Molecule: CH4
indicate the number of
available electrons that are
in the molecule.
ae =
Trial Structure:
in the space to the right
connect all of the atoms
to the central atom and
then make each atom
follow the octet rule (duet
rule for hydrogen).
How many electrons are
necessary in the trial
structure?
Circle the correct
ne =
ne = ae
ne < ae
ne>ae
relationship between ne
and ae.
Draw the corrected Lewis
Structure to the right.
Add Later:
e- geometry:
molecular geom
Hybridization:
Transcribed Image Text:3. Molecule: CH4 indicate the number of available electrons that are in the molecule. ae = Trial Structure: in the space to the right connect all of the atoms to the central atom and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? Circle the correct ne = ne = ae ne < ae ne>ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geom Hybridization:
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