8. Consider the following structure, where the C-C and C=C bond lengths are drawn roughly to scale of the actual molecule. In other words, two different bond lengths were measured/observed for this compound (i.e. the C=C bond length is different than the C-C length).
8. Consider the following structure, where the C-C and C=C bond lengths are drawn roughly to scale of the actual molecule. In other words, two different bond lengths were measured/observed for this compound (i.e. the C=C bond length is different than the C-C length).
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Are the bond lengths data consistent with a resonance model? Yes or no? Please explain thank you.
![8. Consider the following structure, where the C-C and C=C bond lengths are drawn roughly to
scale of the actual molecule. In other words, two different bond lengths were
measured/observed for this compound (i.e. the C=C bond length is different than the C-C
length).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F81378cae-4808-4668-a351-a1b3856204ab%2F13b5a9ca-a775-41eb-b844-f87f687b617d%2Feprq8x7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:8. Consider the following structure, where the C-C and C=C bond lengths are drawn roughly to
scale of the actual molecule. In other words, two different bond lengths were
measured/observed for this compound (i.e. the C=C bond length is different than the C-C
length).
Expert Solution
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Step 1
In cyclobutadiene two C=C bonds are present. But, due to ring strain the pi-orbital are orthogonal. That's why they don't undergo resonance heavily. That's why in cyclobutadiene two C-C bonds and two C=C bonds are present.
As we know single bond length is always greater than double bond length.
That's why in cyclobutadiene two C-C bond lengths are present.
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