FC = VE NBE +BE

Pushing Electrons
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ISBN:9781133951889
Author:Weeks, Daniel P.
Publisher:Weeks, Daniel P.
Chapter1: Lewis Structures
Section: Chapter Questions
Problem 34EQ: Chloromethane has the Lewis structure _______________________________ The carbon atom is sharing 4...
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O 0,6, 2
0, 3, 0
-1, 3, 0
H2N°
FC = VE
NBE +
BE
1
FC = VE -(NBE + BE)
2
Prompts
O 0, 2, 0
-1, 6, 2
0, 4, 4
FC formula
Transcribed Image Text:O 0,6, 2 0, 3, 0 -1, 3, 0 H2N° FC = VE NBE + BE 1 FC = VE -(NBE + BE) 2 Prompts O 0, 2, 0 -1, 6, 2 0, 4, 4 FC formula
Determine the 1) formal charge (FC), number of 2) bonding electrons (BE), 3) non-bonding electrons (NBE) of the following. Hint: Add
any lone pairs as necessary and determine the number of valence electrons (VE) from the periodic table.
...
H2N°
CH2
Transcribed Image Text:Determine the 1) formal charge (FC), number of 2) bonding electrons (BE), 3) non-bonding electrons (NBE) of the following. Hint: Add any lone pairs as necessary and determine the number of valence electrons (VE) from the periodic table. ... H2N° CH2
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