Members of the city council want to know if a majority of city residents supports a 1% increase in the sales tax to fund road repairs. To investigate, they survey a random sample of 300 city residents and use the results to test the following hypotheses: Họ: p = 0.50 Hp > 0.50 where pis the proportion of all city residents who support a 1% increase in the sales tax to fund road repairs. In the sample, p = 158/300 = 0.527. The resulting P-value is 0.18. What is the correct interpretation of this P-value? Assuming that 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. There is an 18% chance that the majority of residents supports the tax increase. Assuming that 50% of residents support the tax increase, there is an 18% chance that the null hypothesis is true by chance alone. Assuming that more than 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. Only 18% of the city residents support the tax increase.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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Members of the city council want to know if a majority of city residents supports a 1% increase in the sales tax to fund road
repairs. To investigate, they survey a random sample of 300 city residents and use the results to test the following hypotheses:
Họ: p = 0.50
Hip > 0.50
where pis the proportion of all city residents who support a 1% increase in the sales tax to fund road repairs.
In the sample, p = 158/300 = 0.527. The resulting P-value is 0.18. What is the correct interpretation of this P-value?
Assuming that 50% of residents support the tax increase, there is an 18% probability that the sample proportion would
be 0.527 or greater by chance alone.
There is an 18% chance that the majority of residents supports the tax increase.
Assuming that 50% of residents support the tax increase, there is an 18% chance that the null hypothesis is true by
chance alone.
Assuming that more than 50% of residents support the tax increase, there is an 18% probability that the sample
proportion would be 0.527 or greater by chance alone.
Only 18% of the city residents support the tax increase.
Transcribed Image Text:Members of the city council want to know if a majority of city residents supports a 1% increase in the sales tax to fund road repairs. To investigate, they survey a random sample of 300 city residents and use the results to test the following hypotheses: Họ: p = 0.50 Hip > 0.50 where pis the proportion of all city residents who support a 1% increase in the sales tax to fund road repairs. In the sample, p = 158/300 = 0.527. The resulting P-value is 0.18. What is the correct interpretation of this P-value? Assuming that 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. There is an 18% chance that the majority of residents supports the tax increase. Assuming that 50% of residents support the tax increase, there is an 18% chance that the null hypothesis is true by chance alone. Assuming that more than 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. Only 18% of the city residents support the tax increase.
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