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Members of the city council want to know if a majority of city residents supports a 1% increase in the sales tax to fund road repairs. To investigate, they survey a random sample of 300 city residents and use the results to test the following hypotheses: Họ: p = 0.50 Hp > 0.50 where pis the proportion of all city residents who support a 1% increase in the sales tax to fund road repairs. In the sample, p = 158/300 = 0.527. The resulting P-value is 0.18. What is the correct interpretation of this P-value? Assuming that 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. There is an 18% chance that the majority of residents supports the tax increase. Assuming that 50% of residents support the tax increase, there is an 18% chance that the null hypothesis is true by chance alone. Assuming that more than 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. Only 18% of the city residents support the tax increase.

Members of the city council want to know if a majority of city residents supports a 1% increase in the sales tax to fund road repairs. To investigate, they survey a random sample of 300 city residents and use the results to test the following hypotheses: Họ: p = 0.50 Hp > 0.50 where pis the proportion of all city residents who support a 1% increase in the sales tax to fund road repairs. In the sample, p = 158/300 = 0.527. The resulting P-value is 0.18. What is the correct interpretation of this P-value? Assuming that 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. There is an 18% chance that the majority of residents supports the tax increase. Assuming that 50% of residents support the tax increase, there is an 18% chance that the null hypothesis is true by chance alone. Assuming that more than 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. Only 18% of the city residents support the tax increase.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Members of the city council want to know if a majority of city residents supports a 1% increase in the sales tax to fund road repairs. To investigate, they survey a random sample of 300 city residents and use the results to test the following hypotheses: Họ: p = 0.50 Hip > 0.50 where pis the proportion of all city residents who support a 1% increase in the sales tax to fund road repairs. In the sample, p = 158/300 = 0.527. The resulting P-value is 0.18. What is the correct interpretation of this P-value? Assuming that 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. There is an 18% chance that the majority of residents supports the tax increase. Assuming that 50% of residents support the tax increase, there is an 18% chance that the null hypothesis is true by chance alone. Assuming that more than 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. Only 18% of the city residents support the tax increase.
Transcribed Image Text:Members of the city council want to know if a majority of city residents supports a 1% increase in the sales tax to fund road repairs. To investigate, they survey a random sample of 300 city residents and use the results to test the following hypotheses: Họ: p = 0.50 Hip > 0.50 where pis the proportion of all city residents who support a 1% increase in the sales tax to fund road repairs. In the sample, p = 158/300 = 0.527. The resulting P-value is 0.18. What is the correct interpretation of this P-value? Assuming that 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. There is an 18% chance that the majority of residents supports the tax increase. Assuming that 50% of residents support the tax increase, there is an 18% chance that the null hypothesis is true by chance alone. Assuming that more than 50% of residents support the tax increase, there is an 18% probability that the sample proportion would be 0.527 or greater by chance alone. Only 18% of the city residents support the tax increase.
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