c. Using Emily's sample results, construct a 90% confidence interval estimate of the proportion of correct responses made by touch therapists.
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- A simple random sample of 500 elements generates a sample proportion p = 0.83. %3D a. Provide the 90% confidence interval for the population proportion (to 4 decimals). b. Provide the 95% confidence interval for the population proportion (to 4 decimals).Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. 95% confidence level; n = 428, x = 71 Round your answer to 4 decimal places.Gender College Engineering Nursing GPA Male 3.01 Female 3.2 Female Arts and Sciences 3.61 Male Engineering 3.2 Male Engineering Health Science 3.72 Female 3.85 Nursing Nursing Health Science Female 3.48 Female 3.2 Female 3.7 Female Education 3.29 Female Arts and Sciences 3.5 Female Education 3.45 Male Engineering Male Business 3.75 Female Nursing 3.4 Nursing Nursing Arts and Sciences Female 3.25 Female 3.67 Female 3.13 Female Education 3.44 Female Health Science 3.76 Male Engineering Engineering Arts and Sciences Health Science 3.14 Male 3.51 Female 3.21 Female 3.28 Female Nursing 3.26 Female Education 3.8 Male Engineering 2.8 Male Business 3.74 Female Business 3.26 Female Nursing 3.4
- In a survey of 2000 adults in a recent year, 713 made a New Year's resolution to eat healthier. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion p is (.D. (Round to three decimal places as needed.)Need 95% interval for all five categories.In a survey of 1036 adults, a poll asked, "Are you worried or not worried about having enough money for retirement?" Of the 1036 surveyed, 649 stated that they were worried about having enough money for retirement. Construct a 99% confidence interval for the proportion of adults who are worried about having enough money for retirement A 99% confidence interval for the proportion of adults who are worried about having enough money for retirement is ( D. (Use ascending order. Round to four decimal places as needed.)
- Need help with statisticsDetermine the t values that correspond to the boundaries for the confidence level desired. If the desired confidence level is 80%, for a sample of n=31 individuals, what t values form the boundaries for the middle 80% and the most extreme 20%?Use the confidence interval to find the margin of error and the sample mean. (1.70,2.08) ... The margin of error is (Round to two decimal piaces as needed.)
- You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You decide on the 90% confidence level and a margin of error of 2%. A pilot survey reveals that 5 of the 44 sampled hold two or more jobs. (Use t Distribution Table & z Distribution Table.) How many in the workforce should be interviewed to meet your requirements? (Round z-score to 2 decimal places. Round up your answer to the next whole number.)Keisha wants to estimate the percentage of managers at her company that hold an MBA. She surveys 320 managers and finds that 70 hold an MBA. Find the margin of error for the confidence interval for the population proportion with a 90% confidence level. z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of common z-scores above. Round the final answer to three decimal places.Find the sample size needed to estimate the percentage of residents of one region of a country who are left-handed. Use a margin of error of six percentage points, and use a confidence level of 99%. Complete parts (a) through (c) below.