A cigarette manufacturer claims that one-eighth of the US adult population smokescigarettes. In a random sample of 100 adults, 5 are cigarette smokers. Test themanufacturer's= 0.05.claim at a =

Given: P = 18 = 0.125 n = 100 X = 5 α = 0.05 Formula Used: Test-statistic Z = p-PP(1-P)n

Answered: A cigarette manufacturer claims that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A group of students need to submit a project and they need to survey people about their daily routine. How many people should they survey in order to be 95% confident that the estimated ( sample) proportion is within three percentage points of the true population? Assume that pq= 0.25
The U.S. Department of Energy reported that 51.7% of homes were heated by natural gas. A random sample of 221 homes in Kentucky found that 115 were heated by natural gas. Does the evidence support the claim for Kentucky at the a = 0.05 level? Are the results applicable across the country? Why?
A recent study claims that 40% of registered voters associate themselves with Democrats. 35% with Republicans, 20% Independent, 3% Green party, and 2% with Social democrats. In a sample of 400 individuals, we observed Actual 200 Democrats 150 Republicans 25 Independent 15 Green Party 10 Social Democrats Test the claim at a=0.05.
A county environmental agency suspects that the fish in a particular polluted lake have elevated mercury levels. To confirm that suspicion, five striped basses in that lake were caught and their tissues were tested for mercury. For the purpose of comparison, four striped basses in an unpolluted lake were also caught and tested. The fish tissue mercury levels in mg/kg are given below. Sample I(From Polluted Lake) 0.523 0.723 0.523 0.623 0.523 Sample II(From Unpolluted Lake) 0.323 0.223 0.523 0.323 0.000 (a) Construct the 95% confidence interval for the difference in the population means based on these data. (b) Test, at the 5% level of significance, whether the data provide sufficient evidence to conclude that fish in the polluted lake have elevated levels of mercury in their tissue.
A magazine provided results from a poll of 1500 adults who were asked to identify their favorite pie. Among the 1500 respondents, 14% chose chocolate pie, and the margin of error was given as ±5 percentage points. Describe what is meant by the statement that "the margin of error was given as ±5 percentage points." Choose the correct answer below. A. The statement indicates that the study is only 5% confident that the true population percentage of people that prefer chocolate pie is exactly 14%. B. The statement indicates that the true population percentage of people that prefer chocolate pie is in the interval 14%±5%. C. The statement indicates that the interval 14%±5% is likely to contain the true population percentage of people that prefer chocolate pie.
untreated depression will lose at least one friendship while not receiving treatment. On the other hand, when people with depression are treated with medication and counseling, only 2 out of 100 will lose at least one friendship during treatment. The absolute risk of losing at least one friendship while dealing with untreated depression is Answer: 25 / 100 = 0.25 = 25%
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A researcher believes that 52.5% of people who grew up as the only child have an IQ score over 100. However, unknown to the researcher, this figure is actually 50%, which is the same as in the general population.To attempt to find evidence for the claim, the researcher is going to take a random sample of 400 people who grew up as the only child. Let p be the proportion of people in the sample with an IQ score above 100. Answer the following: a) Find the mean of p: b)Find the standard deviation of p: c) Compute an approximation for P(p ≥ 0.525), which is the probability that there will be 52.5% or more people with IQ scores over 100 in the sample. Round your answer to four decimal places.
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A cigarette manufacturer claims that one-eighth of the US adult population smokes cigarettes. In a random sample of 100 adults, 5 are cigarette smokers. Test the manufacturer's claim at a = 0.05.