please help solve attached below are questions pertaining to attached find the test statisitc find the p valueState the conclusion for the test. A.Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. iMore InfoCity #1103City #211786501211001138510187104107213110135111290143100133267101145209PrintDone Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample ofbaby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selectedfrom normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance levelto test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents.Click the icon to view the data table of strontium-90 amounts.What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2consists of amounts from city #2.O A. Ho: H1 #H2H1:41> H2B. Ho: H1 SH2H1: H1 > H2C. Ho: H1 = H2H1: H1> H2D. Ho: H1 = H2H1: Hy # H2The test statistic is(Round to two decimal places as needed.)

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Description: please help solve attached below are questions pertaining to attached find the test statisitc find the p valueState the conclusion for the test. A.Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amoun

The two-sample test statistic is used when we have the following conditions: i) Data in each group…

Answered: Listed in the data table are amounts of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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please help solve attached below are questions pertaining to attached

find the test statisitc

find the p value

State the conclusion for the test.

A.Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.

B. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.

C. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.

D. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater.

i
More Info
City #1
103
City #2
117
86
50
121
100
113
85
101
87
104
107
213
110
135
111
290
143
100
133
267
101
145
209
Print
Done

Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of
baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected
from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level
to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents.
Click the icon to view the data table of strontium-90 amounts.
What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2
consists of amounts from city #2.
O A. Ho: H1 #H2
H1:41> H2
B. Ho: H1 SH2
H1: H1 > H2
C. Ho: H1 = H2
H1: H1> H2
D. Ho: H1 = H2
H1: Hy # H2
The test statistic is
(Round to two decimal places as needed.)

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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