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Assume your a is .01. What should be their decision about the null hypothesis and the conclusion for the study from Question 1? Again, use the z-table for this question. Do not reject; the threshold was equivalent to 95% of the area under the curve (p = .05). b. Reject; the sample mean was less than the threshold that represented 99% of the area under the curve, hence p>.01. c. Reject; the sample mean was above the threshold that represented 99% of the area under the curve, hence p<.01. %3D а.

Assume your a is .01. What should be their decision about the null hypothesis and the conclusion for the study from Question 1? Again, use the z-table for this question. Do not reject; the threshold was equivalent to 95% of the area under the curve (p = .05). b. Reject; the sample mean was less than the threshold that represented 99% of the area under the curve, hence p>.01. c. Reject; the sample mean was above the threshold that represented 99% of the area under the curve, hence p<.01. %3D а.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Please answer question 3.
**Question #1** For a just-completed research project, the null hypothesis of the researchers was that the sample mean was equal to the population mean. Or in equation form: M = μ. At the conclusion of the study, the following information was known: - μ = 32.4 - M = 35.6 - σ = 6.3 - n = 25 *See page 5 of your notes if you cannot remember what these symbols mean.* The formula to calculate Z for a population is: Z = M - μ / (σ/√n). Note that the formula differs from a sample Z which you have calculated in the past. You may calculate the numerator and denominator separately, then calculate the actual Z. a. 2.54 b. 1.56 c. 2.35 d. 1.6 **Question #2** Assume your α = .05. What should be their decision about the null hypothesis and the conclusion for the study from Question 1? Use the Z-table for this question. *HINT: Does the Z go beyond the threshold that represents 95% of the area under the curve? If so your null is rejected. Apply this logic to the following question.* **Hint:** Is the sample mean far enough from the population mean at the .05 level? a. Do not reject; the threshold was equivalent to 95% of the area under the curve (p = .05). b. Reject; the sample mean was less than the threshold that represented 95% of the area under the curve, hence p > .05. c. Reject; the sample mean was above the threshold that represented 95% of the area under the curve, hence p < .05.
Transcribed Image Text:**Question #1** For a just-completed research project, the null hypothesis of the researchers was that the sample mean was equal to the population mean. Or in equation form: M = μ. At the conclusion of the study, the following information was known: - μ = 32.4 - M = 35.6 - σ = 6.3 - n = 25 *See page 5 of your notes if you cannot remember what these symbols mean.* The formula to calculate Z for a population is: Z = M - μ / (σ/√n). Note that the formula differs from a sample Z which you have calculated in the past. You may calculate the numerator and denominator separately, then calculate the actual Z. a. 2.54 b. 1.56 c. 2.35 d. 1.6 **Question #2** Assume your α = .05. What should be their decision about the null hypothesis and the conclusion for the study from Question 1? Use the Z-table for this question. *HINT: Does the Z go beyond the threshold that represents 95% of the area under the curve? If so your null is rejected. Apply this logic to the following question.* **Hint:** Is the sample mean far enough from the population mean at the .05 level? a. Do not reject; the threshold was equivalent to 95% of the area under the curve (p = .05). b. Reject; the sample mean was less than the threshold that represented 95% of the area under the curve, hence p > .05. c. Reject; the sample mean was above the threshold that represented 95% of the area under the curve, hence p < .05.
**Question #3** Assume your α is .01. What should be their decision about the null hypothesis and the conclusion for the study from Question 1? Again, use the z-table for this question. a. Do not reject; the threshold was equivalent to 95% of the area under the curve (p = .05). b. Reject; the sample mean was less than the threshold that represented 99% of the area under the curve, hence p > .01. c. Reject; the sample mean was above the threshold that represented 99% of the area under the curve, hence p < .01. --- **Question #4** Assume your α is .001. What should be their decision about the null hypothesis and the conclusion for the study from Question 1? Again, use the z-table for this question. a. Reject; the sample mean was beyond the threshold that represented 99.9% of the area under the curve, hence p < .001. b. Do not reject. The sample mean was NOT beyond the threshold that represented 99.9% of the area under the curve, hence p > .001. c. Reject; the sample mean was NOT beyond the threshold that represented 99.9% of the area under the curve, hence p < .001.
Transcribed Image Text:**Question #3** Assume your α is .01. What should be their decision about the null hypothesis and the conclusion for the study from Question 1? Again, use the z-table for this question. a. Do not reject; the threshold was equivalent to 95% of the area under the curve (p = .05). b. Reject; the sample mean was less than the threshold that represented 99% of the area under the curve, hence p > .01. c. Reject; the sample mean was above the threshold that represented 99% of the area under the curve, hence p < .01. --- **Question #4** Assume your α is .001. What should be their decision about the null hypothesis and the conclusion for the study from Question 1? Again, use the z-table for this question. a. Reject; the sample mean was beyond the threshold that represented 99.9% of the area under the curve, hence p < .001. b. Do not reject. The sample mean was NOT beyond the threshold that represented 99.9% of the area under the curve, hence p > .001. c. Reject; the sample mean was NOT beyond the threshold that represented 99.9% of the area under the curve, hence p < .001.
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